mikey_b Posted January 26, 2010 Share Posted January 26, 2010 Hi all, POSTED YESTERDAY IN MYSQL SECTION - PROBABLY THE WRONG SECTION!!! (+ have now used php tags with snippet) I'm sorry I don't come around here much - but please could someone help...you've always been so helpful here. A year or two ago I taught myself some php and mysql in order to create my first ever database. It's worked fine eversince (though I'm sure the snippet of code I've included below is probably extremely basic and a bit long in the tooth too!!!) I've just upgraded my VPS hosting and it has gone from MySQL 4 to version 5.0.5(?) and I'm getting the following error when tryint to run the pages... "Parse error: syntax error, unexpected ';' in /var/www/vhosts/vintage-home.co.uk/httpdocs/textile_pages/textiles_fabpage.php on line 183 " The follwing code is the whole 'piece' from around that line number - the code on line 183 is that in line 4 shown below (begins 'else {echo ?> onclick...') Could someone please tell me where I'm going wrong or what syntax rules have chaged... ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ <div id="polaroid_outer1" <?php if ($row_rs_textiles['image_1'] == "tx") { echo ">"; } else { echo ?> onclick="MM_goToURL('parent','../index_fab10.php?ItemCode=<?php echo $row_rs_item1['ItemCode'];?>&pagenum=<?php echo $row_rs_textiles['page_number']; ?>');return document.MM_returnValue"> <?php }?> <div id="polaroid1_status"> <?php if ($row_rs_item1['Status'] == "S") {$polaroid_overlay1 = '../images_fab/vh_sold1.png';?> <img src= <?php echo $polaroid_overlay1; ?> border="0"/> <?php } ?> <?php if ($row_rs_item1['Status'] == "R") {$polaroid_overlay1 = '../images_fab/VH_reserved1.png';?> <img src= <?php echo $polaroid_overlay1; ?> border="0"/> <?php } ?> <?php if($row_rs_textiles['image_1'] == "tx") { echo "$largeblank"; } ?> </div> <div id="pos_polaroid1"> <img src= <?php echo ("../textile_files/".$row_rs_item1['ItemCode']."/".$row_rs_item1['ItemCode']."_polaroid1.jpg");?> border="0"/></div> <div id="pos_item_name1" align="center" class="polaroid_title"> <?php if($row_rs_textiles['image_1'] == "tx") { echo "Watch this space..."; } else { echo $row_rs_item1['ItemTitle'];} ?> </div> </div> +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ Kind regards Mikey B Quote Link to comment https://forums.phpfreaks.com/topic/189836-please-help-am-just-a-bit-lost/ Share on other sites More sharing options...
MadTechie Posted January 26, 2010 Share Posted January 26, 2010 change else { echo ?> to else { ?> Quote Link to comment https://forums.phpfreaks.com/topic/189836-please-help-am-just-a-bit-lost/#findComment-1001761 Share on other sites More sharing options...
mikey_b Posted January 26, 2010 Author Share Posted January 26, 2010 MadTechie your a STAR!!!!!! worked beautifully!!!! Could you possibly give me a quickie noob explanation - whatsyntax rules changed and why/where it applies. After making your suggested changes - it then went on to fall-over on later lines - all with the same syntax - when I corrected these it all worked. I can't believe the spped of the response I've had here...wow! I really enjoy doing what little php I can - it brilliant to 'make something happen' through your own coding - and it's why I'm looking for a simple explanation/update on my syntax so I can carry on doing stuff with php - I love it! Kind regards Mike Quote Link to comment https://forums.phpfreaks.com/topic/189836-please-help-am-just-a-bit-lost/#findComment-1001767 Share on other sites More sharing options...
MadTechie Posted January 26, 2010 Share Posted January 26, 2010 Sure, lets create some examples, Here is a simple if statement inside some HTML (inline coding) some HTML<BR /> <?php if(11 > 10){ echo "11 is greater than 10<BR />"; }else{ echo "11 is NOT greater than 10<BR />"; } ?> More HTML output is some HTML 11 is greater than 10 More HTML Now instead of using echo you could just close the PHP tags ie some HTML<BR /> <?php if(11 > 10){ ?> 11 is greater than 10<BR /> <?php }else{ ?> 11 is NOT greater than 10<BR /> <?php } ?> More HTML and we get the same result Now echo require one or more parameters so echo "one"; //one echo "two","three"; // twothree echo "4","5","6"; // 456 echo ; //Failed Parse error: syntax error, unexpected ';' Now lets look at your error, } else { echo ?> onclick="MM_goToURL('parent','../index_fab10.php?ItemCode=<?php echo $row_rs_item1['ItemCode'];?>&pagenum= translates to } else { echo ;echo $row_rs_item1['ItemCode']; when you remove the HTML code onclick="MM_goToURL('parent','../index_fab10.php?ItemCode= Now i know you maybe thinking where did that extra semi-colon come from.. surely it should be echo echo $row_rs_item1['ItemCode']; and get a different error Parse error: syntax error, unexpected T_ECHO Well when you close a PHP tags ?>, it will close the last line for you for example <?php echo "one" ?> is valid (not error) but get in the habit of closing them.. okay i hope that clears things up.. EDIT: As your offline I have marked this as solved, (you can un/solve it with the button bottom left) you can still post here but it save time for members willing to help Quote Link to comment https://forums.phpfreaks.com/topic/189836-please-help-am-just-a-bit-lost/#findComment-1001797 Share on other sites More sharing options...
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