PHP + SQL

[jamkelvl]

Any ideas why this will work in phpmyadmin

 

SELECT * FROM jobs WHERE assigned_to LIKE '%u%';

 

and

 

<?php
<?php
$select = "SELECT * FROM jobs WHERE assigned_to like = '%u%'";
?>

 

does not?

[aebstract]

Well you added an = sign between the two. What doesn't work about it? You should add 

or DIE(mysql_error());

on to the end so that you can find any errors you have.

 

Not to mention you apparently have <?php twice, back to back?

[jamkelvl]

LOL!  I'm notorious for such -what seems like- useless posts...

 

Thank-you for your time!