Response Not getting in AJAX, Pls help me

[mubarakabbas]

Hi.

 

When am checking with firebug, the Response Text "Done" is showing, but the value is not changing in HTML file, innerHTML=xmlhttp.responseText is not changing.  pls help me...

 

 

HTML file To replace:

 

 <div class="row">
     
         <span class="label">أختار اللغة</span>
         <span class="formw"><select size="1" name="Language_ID" onchange="getMenu(this.value)">
               <!-- START BLOCK : Language -->
              <option value="{Language_ID}" {selected}>{Language_Name}</option>
               <!-- END BLOCK : Language -->
              </select></span>
    </div>
    

     <div class="row">
     
         <span class="label">Menu Type</span>
         <span class="formw">
         
         <div id="asdfg">
  		<select style="background-color: #ffffa0" name="state"><option>Select Language First</option> </select></div>
         </span>
    </div>

 

JS FILE

 

// JavaScript Document



var xmlhttp;
//function namechange(name_fieldvalue)

function getMenu(Language_ID)
{
/*
alert(name_fieldvalue);
alert(name_fieldname);
alert(id_val);
alert(id_fieldname);
alert(table_name);
*/
/*
if (name_fieldvalue.length==0)
  {
  document.getElementById("txtHint").innerHTML="";
  return;
  }
  
  */
xmlhttp=GetXmlHttpObject();
if (xmlhttp==null)
  {
  alert ("Your browser does not support XMLHTTP!");
  return;
  }
var url="findmenu.php";
url=url+"?Language_ID="+Language_ID;
xmlhttp.onreadystatechange=stateChanged;
xmlhttp.open("GET",url,true);
xmlhttp.send(null);
}

function stateChanged()
{
if (xmlhttp.readyState==4)
  {
  Response.ContentType = "text/plain";
	Response.Expires = -1;
	Response.CacheControl = "no-cache";

  document.getElementById("asdfg").innerHTML=xmlhttp.responseText;
  }
}

function GetXmlHttpObject()
{
if (window.XMLHttpRequest)
  {
  // code for IE7+, Firefox, Chrome, Opera, Safari
  return new XMLHttpRequest();
  }
if (window.ActiveXObject)
  {
  // code for IE6, IE5
  return new ActiveXObject("Microsoft.XMLHTTP");
  }
return null;
}

 

 

findmenu.php

 

$response = "done";
//output the response
echo $response;