Little else trouble.

[strago]

<?php
$v = $_GET['v'];
if(isset($_GET['v']))

include('http://www.domain.com/video.php?video='.$_GET['v']);

if(isset($_GET['v']))
{
echo <<< END

If domain.com/index.php?v=whatever
<P>
post this.

END;
}
else;{

echo <<< END
<HR>
If domain.com/index.php
<P>
Post this.

END;
}
?>

 

If you go to

 

domain.com/index.php

 

it works just fine. But, if you go to

 

domain.com/index.php?v=whatever

 

you get the stuff for that page, and then the code for domain.com/index.php. How do you get it to just post the code for that page and not include the

 

domain.com/index.php

 

info?

[wildteen88]

This line has a syntax error. Remove the ; (semi-colon) after the else

else;{

 

Other than that issue above your code will function as you described.