Cannot Display Array from Select Statement + Login question

[jponte]

Hi,

I'm new to PHP but so far so goog. I was assigend a project and I'm very close to completion.

 

I have a site that logs you in, sets a cookie, and then what I would like to do is depending on the user loging in, certain records from a table are selected and displayed

 

I have the following code:

 

// Connects to your Database
mysql_connect("localhost", "root", "escrma") or die(mysql_error());
mysql_select_db("rma_portal") or die(mysql_error());

//Set Login Variable with the UserID
$login = $_COOKIE['ID_my_site'];	

echo "This is it set to $login <br><br>";

// Collects data from "users" table 
$data = mysql_query("SELECT * 
	    FROM users, cust_info 
                                   WHERE cust_info.Cust_ID = '.$login'") 
or die(mysql_error());

// puts the "users" info into the $info array 
$info = mysql_fetch_assoc($data);  

//Test Print of Login ID passed value
echo $data; WORKS Resource id #3
echo $info["Cust_Name"]; DOES NOT WORK
echo "$Cust_Name"; DOES NOT WORK

echo "$login <br><br>"; WORKS
echo $info["Cust_Company"]; DOES NOT WORK

 

 

1 Question is why I can echo the $login but then I canot pull anything from the query?

Table users

Cust_ID, Username, Password

Table cust_info

Cust_ID, Cust_Name, Cust_Company, Cust_Phone.....

 

2 I don't know if using the Cookie variable to use the login is a good idea. What would be the best way to pass the username to next page so I can use it in the SELECT ststement. Should I use a _SESSION global?

 

Thanks in advance

[jponte]

The problem was with sintax. I was able to get it going....