words not in list

[sonnieboy]

Hello everyone,

 

I would like to count how words that  do *not* have any of the words in array $frags in them.

 

Can you assist, please?<?php

$mystring = "Some apple is eating my orange but not my watermelon.";

 

function notInList($string) {

 

  $frags = array('as', 'is', 'about', 'us', 'at');

  $parts = explode(' ', strtolower($string));

  $count = 0;

 

  foreach ($parts as $part) {

    if (in_array($part[0], $frags)) {

        echo "$part<br />";

        $count++;

    }

  }

 

  return $count;

}

 

echo notInList($mystring)." words";

?>

 

I am pretty much a newbie to php; sorry.

Thanking you in advance.

 

 

 

[xnowandtheworldx]

<?php
$mystring = "Some apple is eating my orange but not my watermelon about.";
function notInList($string) {
$frags = array('as', 'is', 'about', 'us', 'at');
$words = explode(' ', strtolower($string));
$count = 0;
$replace = array(',','.','\'','!'); //replace common punctuation so that it can still recognize words
foreach($words as $word) {
	if(in_array(str_replace($replace, '', $word), $frags)) {
		echo str_replace($replace, '', $word) . '<br/>';
		$count++;
	}
}

return $count;
}

echo notInList($mystring) . " words.";
?>

 

I commented where you had made your mistake.

 

EDIT: I also made it to remove punctuation so that it can still recognize the word even if it has an ',!. at the end of it.

[sonnieboy]

Thanks alot xnowandtheworldx for the prompt response.

 

I wanted to see a count of words that don't have any of these words:

 

$frags = array('as', 'is', 'about', 'us', 'at');

 

Thanks,

[xnowandtheworldx]

Thanks alot xnowandtheworldx for the prompt response.

 

I wanted to see a count of words that don't have any of these words:

 

$frags = array('as', 'is', 'about', 'us', 'at');

 

Thanks,

 

Ah, okay, sorry about that, well, if you can't figure out how to change it post here, and I will post the updated code and let you know how I set it up.

[sonnieboy]

hi xnowandtheworldx,

 

if you don't mind, can you please post me the updated version?

 

Again, thanks very much.

[sonnieboy]

can anyone, please help, please?

[xnowandtheworldx]

can anyone, please help, please?

 

<?php
$mystring = "Some apple is eating my orange but not my watermelon about.";

function notInList($string) {
    $frags = array('as', 'is', 'about', 'us', 'at');
    $words = explode(' ', strtolower($string));
    $replace = array(',','.','\'','!'); //replace common punctuation so that it can still recognize words
    $count = 0;
    foreach($words as $word) {
        if(!in_array(str_replace($replace, '', $word), $frags)) { //All you had to do was add an ! in front of the in_array, so essentially, it is now trying make sure that the words in $frags are NOT in the string...if that makes sense?
            echo str_replace($replace, '', $word) . '<br/>';
            $count++;
        }
    }
    return $count;
}

echo notInList($mystring) . " words.";
?>

 

I believe this is what you wanted, if it's not just let me know, and I'll see what I can do.

[sonnieboy]

xnowandtheworldx,

 

Thank you very, very much.

 

We are almost there.

 

When I added the actual text that we use here at work, then some works that contain some of those are still showing.

 

Take as an example the letter 'a'.

 

If you add the letter a into the array $frags, then that means that the word apple should not appear on the list because it contains the word 'a' but it still appears on that list.

 

I really appreciate your help.