jdgower Posted March 12, 2010 Share Posted March 12, 2010 Please help First of all, my actual question is much more complicated but if i can find the answer to the below it will probably answer my deeper question... http://www.w3schools.com/php/php_ajax_database.asp At the above URL, it connects to a database to grab the information when you select a person. Let's say that I wanted to modify this so that it actually has a master list of people in the drop down, but not all the people are in one database, they are in 2 different databases. Theres a lot of script here but basically all i did was add 2 lines on the index page (script and div), then copy the selectuser.js and getuser.php and put 2 after everything that [i THINK] is relevant. I would think that i could just change the script at the top of index to: <script type="text/javascript" src="selectuser.js"></script> <script type="text/javascript" src="selectuser2.js"></script> at the div on the index, change it to: <div id="txtHint"><b>Person info will be listed here.</b></div> <div id="txtHint2"><b>Person info will be listed here.</b></div> the script in selectuser2.js (the one i make): var xmlhttp; function showUser(str) { xmlhttp=GetXmlHttpObject(); if (xmlhttp==null) { alert ("Browser does not support HTTP Request"); return; } var url="getuser2.php"; url=url+"?q="+str; url=url+"&sid="+Math.random(); xmlhttp.onreadystatechange=stateChanged; xmlhttp.open("GET",url,true); xmlhttp.send(null); } function stateChanged() { if (xmlhttp.readyState==4) { document.getElementById("txtHint2").innerHTML=xmlhttp.responseText; } } function GetXmlHttpObject() { if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari return new XMLHttpRequest(); } if (window.ActiveXObject) { // code for IE6, IE5 return new ActiveXObject("Microsoft.XMLHTTP"); } return null; } the script for getuser2.php (the one i make): <?php $q=$_GET["q"]; $con = mysql_connect('localhost', 'peter', 'abc123'); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("ajax_demo2", $con); $sql="SELECT * FROM user WHERE id = '".$q."'"; $result = mysql_query($sql); echo "<table border='1'> <tr> <th>Firstname</th> <th>Lastname</th> <th>Age</th> <th>Hometown</th> <th>Job</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['FirstName'] . "</td>"; echo "<td>" . $row['LastName'] . "</td>"; echo "<td>" . $row['Age'] . "</td>"; echo "<td>" . $row['Hometown'] . "</td>"; echo "<td>" . $row['Job'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> The issue I'm having is that it only shows information from the second database, not both. There is probably something wrong with the JS, but i dont know what it is. Thanks in advance for your help! -Jeremy Link to comment https://forums.phpfreaks.com/topic/195034-modifying-w3-script-in-order-to-connect-to-2-dbs-not-working-probably-easy/ Share on other sites More sharing options...
jdgower Posted March 12, 2010 Author Share Posted March 12, 2010 nevermind, figured it out, thanks Link to comment https://forums.phpfreaks.com/topic/195034-modifying-w3-script-in-order-to-connect-to-2-dbs-not-working-probably-easy/#findComment-1025316 Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.