Jump to content

class error when included


king.oslo

Recommended Posts

Good morning,

 

I have this class saved in "class_lib/db.php":

<?php
class DBManager {
protected $_connection;
private $_type;

function __construct($db, $host, $username, $password) {
	$this->_type = $db;
	if ($this->_type == 'mysql') {
		$this->_connection = mysql_connect($host, $username, $password);
		mysql_query('SET NAMES UTF8');
		mysql_query('SET CHARACTER_SET utf8');
	}
}

function dbRead($query) {
	if ($this->_type == 'mysql') {
		$resultat = mysql_query($query, $this->_connection);
		for ($i = 0; $i < mysql_num_rows($resultat); $i++) {
			$array[$i] = mysql_fetch_array($resultat, MYSQL_ASSOC);
		}
	}
	return $array;
}

function dbWrite($query) {
	if ($this->_type == 'mysql') {
		$sql = mysql_query($query);
	}
}
}

 

I also have this instantiation:

<?php
include_once('class_lib/db.php');

$DBManager = new DBManager('mysql', 'host.example.com', 'xxxxxxxx', 'xxxxxxxxxxxx');
print '<pre>';
print_r($DBManager -> dbRead('SELECT * FROM db.table'));
print '</pre>';

 

I get this error:

"Fatal error: Cannot access empty property in /home/category/class_lib/db.php on line 9"

 

Notice:

i only get the error if I try and include the class from a separate file. If I copy the class to the view, I get no error.

 

The question:

Why?

Link to comment
https://forums.phpfreaks.com/topic/195286-class-error-when-included/
Share on other sites

Your code works for me.

 

Best guess is that the actual code being executed is not what you think it is. You either have more than one class_lib/db.php folder/file and the wrong one is being included (due to the php include_path setting) or when you uploaded the db.php file it did not work and an older version of the code is what is being used.

Archived

This topic is now archived and is closed to further replies.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.