MDanz Posted March 19, 2010 Share Posted March 19, 2010 this works, it echoes "worked". <?php $url = "http://www.realgm.com"; $tags = (get_meta_tags($url)) ? get_meta_tags($url) : false; if($tags){ echo "worked"; }else{ echo "failed"; } ?> i've deliberately done this so it doesn't work. It fails to open stream. How do i make the error message invisible?... it should just say "failed". <?php $url = "gssgdd"; $tags = (get_meta_tags($url)) ? get_meta_tags($url) : false; if($tags){ echo "worked"; }else{ echo "failed"; } ?> Quote Link to comment Share on other sites More sharing options...
Psycho Posted March 19, 2010 Share Posted March 19, 2010 if($tags = @get_meta_tags($url)) { echo "worked"; } else { echo "failed"; } Quote Link to comment Share on other sites More sharing options...
strangesoul Posted March 20, 2010 Share Posted March 20, 2010 If You just want to make the error invisible put error_reporting(0) after php tag. i.e., <?php error_reporting(0); ....Your code here.... ?> Do this only if you ensure your code is correct otherwise it might hide the errors that u must know to correct the code. Thanks, Strangesoul. Quote Link to comment Share on other sites More sharing options...
The Little Guy Posted March 20, 2010 Share Posted March 20, 2010 You can do a little bit more with this: <?php $url = 'http://www.realgm.com'; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_HEADER, true); curl_setopt($ch, CURLOPT_AUTOREFERER, TRUE); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE); curl_setopt($ch, CURLOPT_LOW_SPEED_TIME, 10); curl_setopt($ch, CURLOPT_TIMEOUT, 10); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 5); curl_exec($ch); $status = curl_getinfo($ch, CURLINFO_HTTP_CODE); curl_close($ch); if($status == 0){ echo 'Site doesn\'t exist!'; }elseif($status == 200){ echo 'Site is live and working!'; }elseif($status == 404){ echo 'Site is live but document not found!'; }elseif($status == 500){ echo 'Site is live and returned an internal server error!'; } echo '<p>'.$status.'</p>'; ?> Quote Link to comment Share on other sites More sharing options...
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