EchoFool Posted April 2, 2010 Share Posted April 2, 2010 Hey, I have a query which does a "SELECT * " and there are 17 fields. I then added a timestampdiff like this : "SELECT *,TIMESTAMPDIFF(DAY, 'RegisterDate' , '".serverdate()."' ) AS DaysOld" So DaysOld should be position 18... yet i get an offset error.. heres thes script: <?php $SELECT = mysql_query("SELECT *,TIMESTAMPDIFF(DAY, 'RegisterDate' , '".serverdate()."' ) AS DaysOld FROM users WHERE UserID='$UserID'") Or die(mysql_error()); $ProfileArray = mysql_fetch_row($SELECT); ?> Age: <?echo$ProfileArray2[18];?> Days Error: Notice: Undefined offset: 18 in profile.php on line 97 Is it not including DaysOld in the array or something? Link to comment https://forums.phpfreaks.com/topic/197360-array-offset-error/ Share on other sites More sharing options...
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