dazzathedrummer Posted April 13, 2010 Share Posted April 13, 2010 Hi, I found a really useful calendar script here: http://keithdevens.com/software/php_calendar I'd like to use it as a summary of dates booked in a database list, i've been trying for hours to populate the following nested array dynamically but im not getting anywhere. this is the array: <?php $days = array( 2=>array('/weblog/archive/2004/Jan/02','linked-day'), 3=>array('/weblog/archive/2004/Jan/03','linked-day'), 8=>array('/weblog/archive/2004/Jan/08','linked-day'), 22=>array('/weblog/archive/2004/Jan/22','linked-day'), ); echo generate_calendar(2004, 1, $days, 3, '/weblog/archive/2004/Jan'); ?> the number is the day number, the first key in the nested array is a hyperlink and the second is a CSS class. for the time being i'll keep the link and the css class the same - so they will always have the same value. so far i've created a connection to my server and created a while loop that does $days = $row['db_date'] and I can echo out the day numbers that I'm looking for - I just cannot figure out how to add the nested elements??? any advice would be greatly appreciated. Quote Link to comment Share on other sites More sharing options...
taquitosensei Posted April 13, 2010 Share Posted April 13, 2010 This is how I would do this. your database loop goes here { $link="/weblog/archive/".date("Y", strtotime($yourdatefield)."/".date("M",strtotime($yourdatefield))."/".sprintf("%02",date("d", strtotime($yourdatefield))); $class="linked-day"; $days[date("d", strtotime($yourdatefield))]['link']=$link; $days[date("d", strtotime($yourdatefield))]['cssclass']=$class; // OR if you don't need the keynames $days[date("d", strtotime($yourdatefield)))]=array($link,$class); } Quote Link to comment Share on other sites More sharing options...
dazzathedrummer Posted April 13, 2010 Author Share Posted April 13, 2010 excellent!!! I'm almost there, I can get the desired result but only for one date in the list (the last date), I dont think the while loop is looping properly. $link="/weblog/archive/"; $class="linked-day"; while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $days = (array($row['gl_date']=>array($link,$class))); } If I echo out the array using print_r all the dates are there: $link="/weblog/archive/"; $class="linked-day"; while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $days = print_r(array($row['gl_date']=>array($link,$class))); } any ideas? Quote Link to comment Share on other sites More sharing options...
taquitosensei Posted April 13, 2010 Share Posted April 13, 2010 you're overwriting the array each time through your loop so it's only giving you the last one. try this $link="/weblog/archive/"; $class="linked-day"; while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $days[$row['gl_date']] = array($link,$class))); } Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.