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mysql query question


karimali831

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Hi

 

I'm trying to add a 1on1 column to my cup_matches table and insert value "1" if ID in the cups table has value "1" in the 1on1 column or insert value "0" if ID in the cups table has value "0" in the 1on1 column. See attatchments to help.

 

I believe there is something wrong with my code:

 

<?php
$getid=safe_query("SELECT cupID FROM ".PREFIX."cup_matches");
while($ds=mysql_fetch_array($getid)) $cupID = $ds['cupID'];

$is1on1=safe_query("SELECT 1on1 FROM ".PREFIX."cups WHERE ID='$cupID'");
$dl=mysql_fetch_array($is1on1);

mysql_query("ALTER TABLE `".PREFIX."cup_matches`
if($is1on1($cupID))   ADD `1on1` INT( 11 ) NOT NULL default '1' AFTER `einspruch`,
else                     ADD `1on1` INT( 11 ) NOT NULL default '0' AFTER `einspruch`;") 

OR die(PREFIX.'cup_matches <font color="red">failed!</font><br> You have already updated to V4.1.4b!<br />'); 
echo '<center><h2>Successfully updated to V4.1.4b!</h2><br><a href="index.php"><b>View Site</b></a></center>'; 
?>

 

Any help I'll appreciate, thank you.

 

[attachment deleted by admin]

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