Echo banner image based on page name?

[kade119]

Hey all,

 

Newb is back, someone help me work up a small script to dynamically call a specific banner image depending on which page is clicked on...

 

contact.php = contact.jpg

work.php = work.jpg etc..

 

 

thanks, just want to see how it would work - trying to learn

 

 

below is a script that just determines if it 's the index and if not uses an alternate image... just thought this might be somewhere to start from...

<?php
function is_homepage()
{
  return in_array(basename($_SERVER['REQUEST_URI']), array('', 'index.php', 'index.html', '/'));
}

$flash = 'http://www.testsite.com/banner.swf';

if (is_homepage()) {
?>
<object width="550" height="400">
<param name="movie" value="<?php echo $flash ?>">
<embed src="<?php echo $flash ?>" width="550" height="400">
</embed>
</object>
<?php
}
else {
echo '<img src="banner.jpg" alt="Image Banner"/>';
}
?>

[themistral]

You could try something like

 

$banner = substr($_SERVER['REQUEST_URI'], 0, (strlen($_SERVER['REQUEST_URI']))-3).'jpg';

 

This will take the php off the end of the filename and replace it with jpg.

 

That should give you a starting point 

 

[kade119]

is there anyway you can explain the meaning of the code, so i understand it thanks

[jcbones]

substr()

strlen()

$_SERVER['vars']

[kade119]

okay i think i understand it...

 

 

 

here is the additional code to finish this minor script

 

print "<img src=\"$banner\" />"

 

so

substr()  this subtracts .php from the file name

strlen()    this counts how many characters

$_SERVER['vars']  and this .. is the location of the file?

[themistral]

For an explanation of $_SERVER['REQUEST_URI'] take a look at http://www.php.net/manual/en/reserved.variables.server.php

 

So, I am taking the portion of the URL after http://www.mysite.com and manipulating it.

 

$url = $_SERVER['REQUEST_URI'];

This will return /filename.php

 

We will then get use the substr function to get the bit we want for the filename.

 

$banner = substr($_SERVER['REQUEST_URI'], 1);

This says that we want the whole string but to start at the second character (0 being the first).

 

$banner = substr($_SERVER['REQUEST_URI'], 1, (strlen($_SERVER['REQUEST_URI']))-3);

We then want the php extension to be dropped so we find the length of the string and subtract 3 (as php is 3 characters) .

 

$banner = substr($_SERVER['REQUEST_URI'], 1, (strlen($_SERVER['REQUEST_URI']))-3).'jpg';

Then you add the jpg extension.

 

I would suggest googling substr and strlen if you don't know how to use them. Php.net has examples of how to use them as well.

[kade119]

wow... thank you for the breakdown, that helps a lot

 

so if i want to combine my script that identifies if it's the homepage it uses my flash file otherwise it uses my banner function.  Does this look correct?

 

<?php
function is_homepage()
{
  return in_array(basename($_SERVER['REQUEST_URI']), array('', 'index.php', 'index.html', '/'));
}

$flash = 'http://www.testsite.com/banner.swf';

if (is_homepage()) {
?>
<object width="550" height="400">
<param name="movie" value="<?php echo $flash ?>">
<embed src="<?php echo $flash ?>" width="550" height="400">
</embed>
</object>
<?php
}
else {
$banner = substr($_SERVER['REQUEST_URI'], 0, (strlen($_SERVER['REQUEST_URI']))-3).'jpg';

print "<img src=\"$banner\" />"
}
?>

[themistral]

Give it a go and see what happens - you learn more from your mistakes than you will even learn from getting everything right first time. 

 

$banner = substr($_SERVER['REQUEST_URI'], 0, (strlen($_SERVER['REQUEST_URI']))-3).'jpg';

Word of caution, this will return /filename.jpg.

As mentioned in my previous post, use

$banner = substr($_SERVER['REQUEST_URI'], 1, (strlen($_SERVER['REQUEST_URI']))-3).'jpg';

to get rid of the first backslash.

 

Good luck!

[kade119]

$banner = substr($_SERVER['REQUEST_URI'], 1, (strlen($_SERVER['REQUEST_URI']))-3).'jpg';

 

what does the "1" define? does that mean pull one string?

[kade119]

this look better?

 

<?php
function is_homepage()
{
  return in_array(basename($_SERVER['REQUEST_URI']), array('', 'index.php', 'index.html', '/'));
}
$banner = substr($_SERVER['REQUEST_URI'], 1, (strlen($_SERVER['REQUEST_URI']))-3).'jpg';

$flash= '<script type="text/javascript">
	var params = {
		 wmode: "transparent"
	};
	swfobject.embedSWF("_flash/banner_lecdg.swf", "fpBanner", "950", "300", "9.0.0", "expressInstall.swf");
	</script>';
if (is_homepage()) {
echo $flash;
}

else {

echo "<img src=\"$banner\" />";
}
?>

[kade119]

need assistance in complete this function, not sure if i'm implementing it correctly

 

this echo, can it be written like that?

echo "<img src='../graphics/$banner' />";

 

<?php
function is_homepage()
{
  return in_array(basename($_SERVER['REQUEST_URI']), array('', 'index.php', 'index.html', '/'));
}
$banner = substr($_SERVER['REQUEST_URI'], 1, (strlen($_SERVER['REQUEST_URI']))-3).'jpg';

$flash= '<script type="text/javascript">
	var params = {
		 wmode: "transparent"
	};
	swfobject.embedSWF("_flash/banner.swf", "fpBanner", "620", "250", "9.0.0", "expressInstall.swf");
	</script>';
if (is_homepage()) {
echo $flash;
}

else {

echo "<img src='../graphics/$banner' />";
}

?>

 

 

and this is on my page include...

<?php print is_homepage($banner) ?>

[kade119]

i've tested this line and do not think it's acquiring the image based on the file name

 

$banner = substr($_SERVER['REQUEST_URI'], 1, (strlen($_SERVER['REQUEST_URI']))-3).'jpg';

[kade119]

any ideas?

 

really appreciate any assistance