Jump to content

Call to undefined function


tobimichigan

Recommended Posts

Fatal error: Call to undefined function int() in C:\xampp\htdocs\details.php on line 135

 

<?php
						$grade = array("A","B","C","D","E","F");                     

						$adno = $_GET['adno'];
						//$grade[0]=A;
						//$grade[1]=B;
						//$grade[2]=C;
						//$grade[3]=D;
						//$grade[4]=E;
						//$grade[5]=F;
						$adno=$_GET['adno'];
$select = mysql_query("select * from acadinfo where adno='$adno'") or die('<p>Error Retrieving<br/>'.'Error: ' .mysql_error() . '</p>');					echo "<table width='548' border='1'>
	<tr>
		<th width='26' scope='col'>ADMISSION NO.</th>
		<th width='26' scope='col'>MATHEMATICS</th>        
		<th width='26' scope='col'>ENGLISH</th>        
		<th width='26' scope='col'>PHYSICS</th>        
		<th width='26' scope='col'>CHEMISTRY</th>        
		<th width='365' scope='col'>BIOLOGY</th>    
	</tr>
<tr><th scope='row'>$adno</th>";    
$datalist = mysql_fetch_array($select);
//$datalist = htmlspecialchars($datalist);

foreach($datalist as $data){    
if (int($data) >= 80) {
 echo "<td>$grade[0]</td>";
} else {        
	if (int($data) >= 70  && int($data) < 80) { 
	   echo "<td>$grade[1]</td>";
	    } else {
		  if (int($data) >= 60  && int($data) < 70) {
		   echo "<td>$grade[2]</td>";
		   }else {
				if (int($data) >= 50  && int($data) < 60) {
				    echo "<td>$grade[3]</td>";
					  } else {
						if (int($data) >= 40  && int($data) < 50) {
						  echo "<td>$grade[4]</td>";
						     } else {
								if (int($data) <= 39  && int($data) < 40) {
								    echo "<td>$grade[5]</td>";                        
									}                    
								}                
							}            
						}        
					}    
				}    
			}
echo "</tr></table>"; 
?>

 

 

Please can I stand corrected? I m working on student grades...

Line 135-if (int($data) >= 80) {

Link to comment
Share on other sites

Hello Gekko, please could you tell what exactly is making the code output F,F,F,FF, instead of the real grades?

Here's my code:

 

<?php
						$grade = array("A","B","C","D","E","F");                     

						$adno = $_GET['adno'];
						$grade[0]=A;
						$grade[1]=B;
						$grade[2]=C;
						$grade[3]=D;
						$grade[4]=E;
						$grade[5]=F;
						$adno=$_GET['adno'];
$select = mysql_query("select * from acadinfo where adno='$adno'") or die('<p>Error Retrieving<br/>'.'Error: ' .mysql_error() . '</p>');					echo "<table width='548' border='1'>
	<tr>
		<th width='26' scope='col'>ADMISSION NO.</th>
		<th width='26' scope='col'>MATHEMATICS</th>        
		<th width='26' scope='col'>ENGLISH</th>        
		<th width='26' scope='col'>PHYSICS</th>        
		<th width='26' scope='col'>CHEMISTRY</th>        
		<th width='365' scope='col'>BIOLOGY</th>    
	</tr>
<tr><th scope='row'>$adno</th>";    
$datalist = mysql_fetch_array($select);
$num=mysql_num_rows($select);
//$datalist = htmlspecialchars($datalist);

foreach($datalist as $data){    
if (intval($data) >= 80) {
 echo "<td>$grade[0]</td>";
} else {        
	if (intval($data) >= 70  && intval($data) < 80) { 
	   echo "<td>$grade[1]</td>";
	    } else {
		  if (intval($data) >= 60  && intval($data) < 70) {
		   echo "<td>$grade[2]</td>";
		   }else {
				if (intval($data) >= 50  && intval($data) < 60) {
				    echo "<td>$grade[3]</td>";
					  } else {
						if (intval($data) >= 40  && intval($data) < 50) {
						  echo "<td>$grade[4]</td>";
						     } else {
								if (intval($data) <= 39  && intval($data) < 40) {
								    echo "<td>$grade[5]</td>";                        
									}                    
								}                
							}            
						}        
					}    
				}    
			}
echo "</tr></table>"; 
?>

By the way the int problem was solved by implementing your correction...thanks

Link to comment
Share on other sites

$datalist = mysql_fetch_array($select);
$num=mysql_num_rows($select);
//$datalist = htmlspecialchars($datalist);

foreach($datalist as $data){    
if (intval($data) >= 80) {
 echo "<td>$grade[0]</td>";

 

$data is an ARRAY. You can't get the integer of an arryay. Although there is a lot more wrong with that code.

Link to comment
Share on other sites

Okidoki, a few things....

 

 

                     $grade = array("A","B","C","D","E","F");                     
                     
                     $adno = $_GET['adno'];
                     $grade[0]=A;
                     $grade[1]=B;
                     $grade[2]=C;
                     $grade[3]=D;
                     $grade[4]=E;
                     $grade[5]=F;

 

this is kind of redundant isn't it?

 

you can remove all of this:

                     $grade[0]=A;
                     $grade[1]=B;
                     $grade[2]=C;
                     $grade[3]=D;
                     $grade[4]=E;
                     $grade[5]=F;

 

you've already defined your array of possible grades, there's no need to do it again!

 

for this section of code:

 

foreach($datalist as $data){    
   if (intval($data) >= 80) {
    echo "<td>$grade[0]</td>";
   } else {        
      if (intval($data) >= 70  && intval($data) < 80) { 
         echo "<td>$grade[1]</td>";
          } else {
           if (intval($data) >= 60  && intval($data) < 70) {
            echo "<td>$grade[2]</td>";
            }else {
               if (intval($data) >= 50  && intval($data) < 60) {
                   echo "<td>$grade[3]</td>";
                    } else {
                     if (intval($data) >= 40  && intval($data) < 50) {
                       echo "<td>$grade[4]</td>";
                          } else {
                           if (intval($data) <= 39  && intval($data) < 40) {
                               echo "<td>$grade[5]</td>";                        
                              }                    
                           }                
                        }            
                     }        
                  }    
               }    
            }

 

I'd look at investing in some elseif() statements, seriously

 

so something like this:

 

foreach($datalist as $data)
{
if(intval($data) >= 80)
	{

	 echo "<td>$grade[0]</td>";

	} elseif(intval($data) >= 70  && intval($data) < 80) {

	echo "<td>$grade[1]</td>";

	} elseif(intval($data) >= 60  && intval($data) < 70) {

	echo "<td>$grade[2]</td>";

	} elseif(intval($data) >= 50  && intval($data) < 60) {

	echo "<td>$grade[3]</td>";

	} elseif(intval($data) >= 40  && intval($data) < 50) {

	echo "<td>$grade[4]</td>";

	} elseif(intval($data) <= 39  && intval($data) < 40) {

	echo "<td>$grade[5]</td>";

	}
}

 

thats what the elseif is for!  :D

 

but, check that $data variable, i'm guessing that what you actually want there is something like $data['mark'] instead just $data, because your looking at the element of that array $data

 

jus editing this again :P.. yeah so basically you downloaded your database into that variable $datalist (with entries of each row you've retrieved from the database), which is an array, and each element in that array will be another array - this will be an array for example $dataList[0]['name'], $dataList[0]['mark'], $dataList[0]['birthday'] - or whatever, just depends on how your tables are structured

 

so when you launch into that foreach statment your going through each $dataList element and giving it the name $data, but $data is still an array - because each element of $dataList was an array..

 

am I making sense?

Link to comment
Share on other sites

I dunno if this is necessary, maybe some other forum members could correct me, but this is the way i'd get your $datalist array from the database

 


		$query = mysql_query($select);

		//Build the array
		$i = 0;

		while ($row = mysql_fetch_assoc($query))
			{

			$keys = array_keys($row);

			foreach($keys as $key)
				{

				$datalist[$i] = $row[$key];

				}

			$i++;

			}

instead of

 


$datalist = mysql_fetch_array($select);
$num=mysql_num_rows($select);

Link to comment
Share on other sites

Nah, if you want to go that route, I would set the index of the array as the grade percentage and the value as the letter grade. Then you can get the letter grade by a simple foreach loop

$grades = array(80=>'A', 70=>'B', 60=>'C', 50=>'D', 40=>'E', 0=>'F');

$studentPercent = 75; //Some number from the DB query

foreach($grades as $gradePercent => $letterGrade)
{
    if($studentPercent>$gradePercent) { break; }
}

echo $letterGrade

 

However, I would take a whole different approach. After looking over your code some more, it seems that you should be getting multiple grades from the DB query (one for each column header). I assume the grades for each subject are in a different field name in the database. Here is a rewrite of what you had. Replace the field names as appropriate:

 

<?php

function getLetterGrade($percent)
{
    if(!is_numeric($percent)) { return '--'; }
    if($percent >= 80) { return 'A'; }
    if($percent >= 70) { return 'B'; }
    if($percent >= 60) { return 'C'; }
    if($percent >= 50) { return 'D'; }
    if($percent >= 40) { return 'E'; }
    return 'F';
}

$adno = (int) $_GET['adno'];
$query = "SELECT * FROM acadinfo WHERE adno='{$adno}'";
$result  = mysql_query($query) or die('<p>Error Retrieving<br/>'.'Error: ' .mysql_error() . '</p>');

if(!mysql_num_rows($result))
{
    echo "No records for admission number {$adno}";
}
else
{
    $studentGrades = mysql_fetch_assocay($result);
    echo "<table width=\"548\" border=\"1\">\n";
    echo "  <tr>\n";
    echo "    <th width=\"26\" scope=\"col\">ADMISSION NO.</th>\n";
    echo "    <th width=\"26\" scope=\"col\">MATHEMATICS</th>\n";
    echo "    <th width=\"26\" scope=\"col\">ENGLISH</th>\n";    
    echo "    <th width=\"26\" scope=\"col\">PHYSICS</th>\n";  
    echo "    <th width=\"26\" scope=\"col\">CHEMISTRY</th>\n";
    echo "    <th width=\"365\" scope=\"col\">BIOLOGY</th>\n";  
    echo "  </tr>\n";
    echo "  <tr>\n";
    echo "    <td>{$adno}</td>\n";
    echo "    <td>" . getLetterGrade($studentGrades['MATHEMATICS']) . "</td>\n";
    echo "    <td>" . getLetterGrade($studentGrades['ENGLISH']) . "</td>\n";
    echo "    <td>" . getLetterGrade($studentGrades['PHYSICS']) . "</td>\n";
    echo "    <td>" . getLetterGrade($studentGrades['CHEMISTRY']) . "</td>\n";
    echo "    <td>" . getLetterGrade($studentGrades['BIOLOGY']) . "</td>\n";
    echo "  </tr>\n";
    echo "</table>\n";
}
?>

Link to comment
Share on other sites

My take on this script;

<?php
                    
function get_grade((int)$i) {
if($i > 79) return 'A';
elseif($i > 69 && $i < 80) return 'B';
elseif($i > 59 && $i < 70) return 'C';
elseif($i > 49 && $i < 60) return 'D';
elseif($i > 39 && $i < 50) return 'E';
else return 'F';
}

$adno = $_GET['adno'];
                     
$select = mysql_query("select * from acadinfo where adno='$adno'") or die('<p>Error Retrieving<br/>'.'Error: ' .mysql_error() . '</p>');              
echo "<table width='548' border='1'>
      <tr>
         <th width='26' scope='col'>ADMISSION NO.</th>
         <th width='26' scope='col'>MATHEMATICS</th>        
         <th width='26' scope='col'>ENGLISH</th>        
         <th width='26' scope='col'>PHYSICS</th>        
         <th width='26' scope='col'>CHEMISTRY</th>        
         <th width='365' scope='col'>BIOLOGY</th>    
      </tr>
<tr><td scope='row'>$adno</td>";    

$datalist = mysql_fetch_assoc($select);

foreach($datalist as $data){	

	echo '<td>' . get_grade($data) . '</td>';

}

   echo '</tr></table>';  
   
   
?>

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.