Notice: Undefined variable:

[zavin]

Why is cars in the following code an undefined variable?

$result = mysql_query("SELECT * FROM `carlot`");
$howmanyitems = 0;
while($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
if ($line['buyable'] == 1){
	$cars .= "<td width='25%' align='center'><img src='". $line['image']."' width='100' height='100' style='border: 1px solid #333333'><br>
	". car_popup($line['name'], $line['id']) ."<br>$". $line['cost'] ."<br><a href='carlot.php?buy=".$line['id']."'>[buy]</a></td>";
	$howmanyitems = $howmanyitems + 1;
	if ($howmanyitems == 3){
		$cars.= "</tr><tr>";
		$howmanyitems = 0;
	}
}
}

[OOP]

Hi,

can you please post the complete message that you are getting?

 

regards

[gclx]

Because you are adding stuff (.=) to a variable that doesn't exist. $cars = ""; at the beginning of your code will fix your error. Or change error type to something less strict .

[zavin]

Because you are adding stuff (.=) to a variable that doesn't exist. $cars = ""; at the beginning of your code will fix your error. Or change error type to something less strict .

 

That was it. It's always the small stuff thanks.