Array related question

[david212]

Hello there.

 

I have this php array code:

 

<?php

$xR = array(3 => "ar", "br", 6 => "cr", "de", 10 => "en", "fr");

$xR[8] = "ge";

$xR[] = "hr";

?>

 

what would be the key for "br"? I think it's 4. But when i want to know the value for "hr" using print_r($xR); i'm getting 12 for "hr" . If the last $xR[8] = "ge"; the "hr" won't be the 9? :S by assingning the next increment after used number? Please explain, im confused with this one

 

Thank you

[ChemicalBliss]

To return arrays with indexes, use somethign like print_r($array), or var_dump($array);

 

I'm sure you will get your answer by looking at the arrays them selves.

 

-cb-

[david212]

i've mentioned that i used print_r($array) an got the 12 but why ? Because the last increment stopped at 11? But i'm asking, if the  $xR[8] = "ge, for the "hr" won't be the 9, i mean based on the "8" value incrementing only 8 not 11

[Ken2k7]

Breaking it down:

$xR = array(3 => "ar", "br", 6 => "cr", "de", 10 => "en", "fr");

That gives this:

 

[3] => "ar"

[4] => "br"

[6] => "cr"

[7] => "de"

[10] => "en"

[11] => "fr"

 

 

$xR[8] = "ge";

That says position at 8 will be "ge":

 

[3] => "ar"

[4] => "br"

[6] => "cr"

[7] => "de"

[10] => "en"

[11] => "fr"

[8] => "ge"

 

 

$xR[] = "hr";

Since the last index stopped at 11 when you created the array, the next one is 12, not 9. $xR[8] = "ge"; doesn't do any increment. It just says to store the value of "ge" at index 8. You can run $xR[8] = "ge"; 100 times and it won't change the index because that's just replacing a value.

 

 

[3] => "ar"

[4] => "br"

[6] => "cr"

[7] => "de"

[10] => "en"

[11] => "fr"

[8] => "ge"

[12] => "hr"

 

 

[david212]

Thank you very much  now i understand better !