Using New Keyword in PHP

[abhishekphp6]

I copy pasted the following php code

 

<?php

include('XMPPHP/XMPPHP/XMPP.php');

$conn = new XMPP('talk.google.com', 5222, 'bi.dw.architect@gmail.com', 'pappu617', 'xmpphp', 'gmail.com', printlog=False, $loglevel=LOGGING_INFO);

$conn->connect();

$conn->processUntil('session_start');

$conn->message('abhishes@gmail.com', 'this is a test message');

$conn->disconnect();

?>

 

But it gives me error

 

Parse error: syntax error, unexpected '=' in /var/www/foo.php on line 3

 

Do I need to install something before using new?

 

I am using ubuntu linux 9.1.0 php 5.2.10-2ubuntu6.4

 

 

 

 

[TeddyKiller]

It might be $loglevel=LOGGING_INFO but not sure. You might need to install something.. although, I can say.. we aren't google. I can't help you on that one. Although I suggest.. taking your email and password out of the code..

[Alex]

Yeah, that is the problem. If you want to leave out those parameters just leave them blank.

 

$conn = new XMPP('talk.google.com', 5222, 'bi.dw.architect@gmail.com', 'pappu617', 'xmpphp', 'gmail.com');

[TeddyKiller]

Yeah, that is the problem. If you want to leave out those parameters just leave them blank.

 

$conn = new XMPP('talk.google.com', 5222, 'bi.dw.architect@gmail.com', 'pappu617', 'xmpphp', 'gmail.com');

What if he wanted them in?

[Alex]

Then he would fill them in. From the looks of the code I'd guess that he copied the function declaration which includes default values for those parameters.

[abhishekphp6]

How to edit the message. I have copy pasted my email id and password. I have changed the password... but I want to remove it from here.

[abhishekphp6]

Also, can you please download this library from here http://code.google.com/p/xmpphp/

 

and try to make this code work? for me it simply states that

 

Fatal error: Class 'XMPP' not found in /var/www/XY.php on line 99

 

I am pretty sure that I have included the path to XMPP.php correctly.

[TeddyKiller]

In XY.php, you should have an include

include("xmpp.php");

[abhishekphp6]

I have the include statement.

 

include('XMPPHP/XMPPHP/XMPP.php');

 

Here the file XMPP.php resides in a directory path XMPPHP/XMPPHP under the www directory where the XY.php file resides.

 

I have also kept the case as-is

 

[ignace]

I believe the error occurs due to:

 

printlog=False

 

Which possibly should have been:

 

$printlog=False