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I'm just not seeing an error in this SQL statement. Can anyone help me please?

UPDATE group SET groupname='aaTest 2 group edited', SET basemodel='abh', SET classcode='', SET sin='', SET openmkt=0, SET updateuser='foo', SET updatedate=NOW() WHERE gid=28;

 

But php returns an error when I use this code:

if (!$result=mysqli_query($dbc,$query))

 

 

 

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Sorry. I modified some of the things. Here is the real SQL statement.

UPDATE hgroup SET groupname='aaTest 2 group edited', 
SET basemodel='abh', SET classcode='', SET sin='', SET openmkt=0, 
SET updateuser='chuckr', SET updatedate=NOW() WHERE grid=28;

I ran it through the phpMyAdmin sql processor, and it gave me an error, but everything looked ok. Here is the phpMyadmin sql error:

SQL query:

UPDATE hgroup SET groupname = 'aaTest 2 group edited',
SET basemodel = 'abh',
SET classcode = '',
SET sin = '',
SET openmkt =0,
SET updateuser = 'chuckr',
SET updatedate = NOW( ) WHERE grid =28

MySQL said: Documentation
#1064 - You have an error in your SQL syntax; check the manual that 
corresponds to your MySQL server version for the right syntax to use near 
'SET basemodel='abh', SET classcode='', SET sin='', SET openmkt=0, 
SET updateuser' at line 1 

Oddly enough, all these fields work fine in an INSERT and SELECT statement. So it shouldn't be a problem with the field names, right?

 

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Here is my table layout.

CREATE TABLE `hgroup` (
  `grid` bigint(20) NOT NULL auto_increment,
  `createuser` varchar(15) NOT NULL default '',
  `createdate` datetime NOT NULL default '0000-00-00 00:00:00',
  `updateuser` varchar(15) default NULL,
  `updatedate` datetime default NULL,
  `groupname` varchar(80) NOT NULL default '',
  `image1` varchar(30) default NULL,
  `classcode` char(3) default NULL,
  `sin` varchar(30) default NULL,
  `openmkt` tinyint(1) NOT NULL default '0',
  `col1name` varchar(50) default NULL,
  `basemodel` varchar(50) default NULL,
  PRIMARY KEY  (`grid`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 AUTO_INCREMENT=33 ;

 

When I reduce my query down to this:


UPDATE hgroup SET groupname='aaTest 1 edited again', SET basemodel='AZA' WHERE grid=30;

I start getting errors. That means, the field 'basemodel' is giving me errors somehow.

 

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