Need some help with build array of a folder

[jim.davidson]

I'm trying to populate a dropdown menu from the names of picture files in a directory.

I'm following some code from a book and it's not working.  I think it because of the variable $theFolder (line 98 of code). Could someone tell me why this code doesn't work?

 

 

 

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[foxsoup]

It's possibly failing because the directory doesn't exist ('../Misc' as set on line 72), but hard to tell for sure without knowing the exact error message.  If you just want a simple bit of code to scan a directory on the server for image files then this should do the trick though:

 

<?php

$dirToScan = '.';  // Directory to scan (current dir)
$imgExts = array('jpg', 'jpeg', 'png', 'gif', 'bmp');  // Array of possibly image file extensions
$imgFiles = array();  // Create blank results array

$allFiles = scandir($dirToScan);  // Get all files in dir into an array
foreach ($allFiles as $filename) {  // Loop through each
$fileInfo = pathinfo($filename);  // Get the info of each file
if (in_array($fileInfo['extension'], $imgExts)) {  // Check to see if file ext is in array
	$imgFiles[] = $filename;  // If so, add the filename to results array
}
}

var_dump($imgFiles);  // Print the results

?>

[jim.davidson]

My problem was the way I was describing the folder name. i.e. '../Misc/'

 

Once I looked at your example and chaged my folder name to 'Misc' it works.

 

Thank You for your help