Subtracting from a date

[TapeGun007]

Hi, I have a very simple problem that I don't quite understand.

 

In php 4.2, I could use this line:

$year = $tempyear -1; 

works fine. 

 

However, in php 5.2 $year becomes equal to nothing.  What's the correct way to write this code now?

[PFMaBiSmAd]

There's nothing wrong with the line of code you posted. It will subtract one from any value in $tempyear and assign that to $year, even if $tempyear does not exist or is a null value or if it is a character string.

 

How do you know you are getting nothing? What value should you be getting? What is your actual code that exhibits the problem?

[TapeGun007]

 

  >.<

 

hmm... weird.  I thought I had put an echo statement to show the year and it was coming up.  Now it isn't at all.  I simply assigned the year the correct value and it works fine.

 

I'm not sure what I was seeing originally or what I did, but I must've made an error somewhere in my troubleshooting. LOL.  Originally, I was getting an error on this: $days_in_month = cal_days_in_month(CAL_GREGORIAN, $month, $year) ;  because $year had no value.  I thought maybe cal_days_in_month had changed, so I echoed the $year to find it had no value.  I then placed that echo command earlier and ... well... I thought it was returning a value... I guess not.