end of string help

[MDanz]

when i echo... how do i get the end of the string.

 

i want to see if the end of the string is an image format.

 

e.g.  .jpeg, .gif, .bmp

 

so

 

if($variable ends with image format) {} else {}

[Alex]

pathinfo

 

$arr = array('jpg', 'bmp', 'gif', 'png' /* ... */);
$info = pathinfo($variable, PATHINFO_EXTENSION);
if(in_array($info['extension'], $arr)){
    // ...
}

[MDanz]

can't seem to get this working.

 

I put the variable $info as test.jpg

 

$arr = array('jpg', 'bmp', 'gif', 'png' /* ... */);
			$check = pathinfo($info, PATHINFO_EXTENSION);
			if(in_array($check['extension'], $arr)){

			$query = "INSERT INTO Stacks";
				  $query .= "(`username`,`image`,`reply`,`number`,`ip`,`origin`,`keywords`,`avatar`,`Positive`,`Negative`) VALUES ('$usernames','$reply','$reply $info','$id','$ip',$org+1,'$keywords','$avatarreply','$pos1','$neg1')";
				  $results = mysql_query($query, $dlink);

echo "worked";
			} else {
				  
				  
				   $query = "INSERT INTO Stacks";
				  $query .= "(`username`,`reply`,`number`,`ip`,`origin`,`keywords`,`avatar`,`Positive`,`Negative`) VALUES ('$usernames','$reply $info','$id','$ip',$org+1,'$keywords','$avatarreply','$pos1','$neg1')";
				  $results = mysql_query($query, $dlink);

echo "didn't work";
				  }

 

 

it should echo didn't work..

[Alex]

My mistake, I forgot that pathinfo doesn't return an array when you specify a specific option to return.

 

$arr = array('jpg', 'bmp', 'gif', 'png' /* ... */);
if(in_array(pathinfo($variable, PATHINFO_EXTENSION), $arr)){
    // ...
}