myscripting Posted June 9, 2010 Share Posted June 9, 2010 I have two scripts. One is a tinyurl API and the other gnerates random strings. What I want to do it pass a random string into the tiny URL API script such that the tiny URL generated is always different <?php function createRandomPassword() { $chars = "abcdefghijkmnopqrstuvwxyz023456789"; srand((double)microtime()*1000000); $i = 0; $pass = '' ; while ($i <= 7) { $num = rand() % 33; $tmp = substr($chars, $num, 1); $pass = $pass . $tmp; $i++; } return $pass; } // Usage $password = createRandomPassword(); ?> <?php //gets the data from a URL function get_tiny_url($url) { $ch = curl_init(); $timeout = 5; curl_setopt($ch,CURLOPT_URL,'http://tinyurl.com/api-create.php?url='.$url); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout); $data = curl_exec($ch); curl_close($ch); return $data; } //test it out! $new_url = get_tiny_url('http://domain.com/?password); echo $new_url ?> where it says http://domain.com/?password i want the password value in the first script to be passed before a tiny url is generated thanks Quote Link to comment https://forums.phpfreaks.com/topic/204334-how-to-pass-a-random-string-into-another-variable/ Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.