does this exist in a class?

[slimboy007]

I have a question which i am not sure how to answer can anyone help please?

Using PHP, determine whether the method 'simple_sum' exists in the class Exam.

 

class Exam{

  public function simple_sum(){

    return null;

  }

}

[jonsjava]

sounds like schoolwork. No cheating.

[bugcoder]

<?php

class myclass {
    // constructor
    function myclass()
    {
        return(true);
    }

    // method 1
    function myfunc1()
    {
        return(true);
    }

    // method 2
    function myfunc2()
    {
        return(true);
    }
}

$class_methods = get_class_methods('myclass');
// or
$class_methods = get_class_methods(new myclass());

foreach ($class_methods as $method_name) {
    echo "$method_name\n";
}

?> 

The above example will output:

 

 

myclass

myfunc1

myfunc2

 

 

[jonsjava]

dirty way. Ok, I'll show the proper method:

<?php 
class test{
public function test2(){
	echo "hello";
}
}
$test = new test();
if (method_exists(test,test2)){
echo "found method";
}
?>

[Alex]

dirty way. Ok, I'll show the proper method:

<?php 
class test{
public function test2(){
	echo "hello";
}
}
$test = new test();
if (method_exists(test,test2)){
echo "found method";
}
?>

 

The first parameter has to either be a string of name of the class you're testing or either an instance of the class. So in your example either 'test' or $test. The second parameter has to be a string, 'test2'.

 

if (method_exists($test, 'test2')){
echo "found method";
}

 

or

 

if (method_exists('test', 'test2')){
echo "found method";
}

[jonsjava]

 

The first parameter has to either be a string of name of the class you're testing or either an instance of the class. So in your example either 'test' or $test. The second parameter has to be a string, 'test2'.

 

if (method_exists($test, 'test2')){
echo "found method";
}

 

or

 

if (method_exists('test', 'test2')){
echo "found method";
}

Forgot to mention that. Thanks, Alex.