tiota Posted July 9, 2010 Share Posted July 9, 2010 how to compare $timeout variable with another string. Lets say $timeout = "00:00:00" in my database, and I want to check whether $timeout contains the string value 00:00:00 I tried this in my code it did not work correctly if ($timeout =="00:00:00") { echo "User did not sign-out "; } esle{ echo "User signed out"; } Quote Link to comment Share on other sites More sharing options...
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