dink87522 Posted July 21, 2010 Share Posted July 21, 2010 $date = time(); $query = "SELECT * FROM experience_process"; $result = mysql_query($query) or die("Error: Could not be completed." . mysql_error()); $process = mysql_fetch_assoc($result); $count = mysql_num_rows($result); echo("<br />date: $date"); echo("<br />Count: $count"); do { // Keeps getting the next row until there are no more to get $user = $row['user_name']; echo("<br />User: $user"); } while ($row = mysql_fetch_assoc($result)); I want to loop through all the users (and echo their name). The above code does not get the first result from the table (so I stopped using a loop and tried a do loop, although same thing), what do I need to do to change this? Quote Link to comment https://forums.phpfreaks.com/topic/208386-looping-first-value-is-being-omitted/ Share on other sites More sharing options...
dezkit Posted July 21, 2010 Share Posted July 21, 2010 remove $process = mysql_fetch_assoc($result); Quote Link to comment https://forums.phpfreaks.com/topic/208386-looping-first-value-is-being-omitted/#findComment-1088967 Share on other sites More sharing options...
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