otester Posted August 4, 2010 Share Posted August 4, 2010 Basically when the page loads it starts with the "man-on-camel" image, fades in/out then displays the "man-on-camel" image again? Why doesn't it start with the "17th-century-brothel-pub.png" image? $("#site_dynamic_content").css("background-image", "url(../images/17th-century-brothel-pub.png)"); $("#site_dynamic_content").fadeIn(2000); $("#site_dynamic_content").fadeOut(2000); $("#site_dynamic_content").css("background-image", "url(../images/man-on-camel.png)"); $("#site_dynamic_content").fadeIn(2000); Any ideas would be great! Thanks, otester Quote Link to comment Share on other sites More sharing options...
radar Posted August 4, 2010 Share Posted August 4, 2010 there are a few generic ways to get this done.. one being: $('img.over').each(function(){ var t=$(this); var src1= t.attr('src'); // initial src var newSrc = src1.substring(src1.lastIndexOf('/'), src1.lastIndexOf('.')); // let's get file name without extension t.hover(function(){ $(this).attr('src', newSrc+ '-over.' + /[^.]+$/.exec(src1)); //last part is for extension }, function(){ $(this).attr('src', newSrc + '.' + /[^.]+$/.exec(src1)); //removing '-over' from the name }); }); you may want to change the class of images from first line. If you need more image classes (or different path) you may use $('img.over, #container img, img.anotherOver').each(function(){ or if you want a bit simpler way of achieving something like this... use CSS #element { width: 100px; /* width of image */ height: 200px; /* width of image */ background-image: url(/path/to/image.jpg); } #element:hover { background-image: url(/path/to/other_image.jpg); } Quote Link to comment Share on other sites More sharing options...
otester Posted August 4, 2010 Author Share Posted August 4, 2010 there are a few generic ways to get this done.. one being: $('img.over').each(function(){ var t=$(this); var src1= t.attr('src'); // initial src var newSrc = src1.substring(src1.lastIndexOf('/'), src1.lastIndexOf('.')); // let's get file name without extension t.hover(function(){ $(this).attr('src', newSrc+ '-over.' + /[^.]+$/.exec(src1)); //last part is for extension }, function(){ $(this).attr('src', newSrc + '.' + /[^.]+$/.exec(src1)); //removing '-over' from the name }); }); you may want to change the class of images from first line. If you need more image classes (or different path) you may use $('img.over, #container img, img.anotherOver').each(function(){ or if you want a bit simpler way of achieving something like this... use CSS #element { width: 100px; /* width of image */ height: 200px; /* width of image */ background-image: url(/path/to/image.jpg); } #element:hover { background-image: url(/path/to/other_image.jpg); } I was trying to make a basic slide show but I did something similar in CSS like you posted, basically making two CSS bits, one with either background and by default set to "display:none", then used jquery to do the fading in/out of either CSS bits along with a JS loops. To stop them both appearing at the same time I had to interleave them (here's code if it'll help anyone else): JavaScript/jQuery: function dynamic() { $("#site_dynamic_content").fadeIn(4000); $("#site_dynamic_content").fadeOut(4000, function() { $("#site_dynamic_content2").fadeIn(5000); $("#site_dynamic_content2").fadeOut(2000, function() { looper(); }); }); } function looper() { dynamic(); } $(document).ready(function(){ dynamic(); }); CSS: #site_dynamic_content { display:none; background-image:url(../images/17th-century-brothel-pub.png); background-repeat:no-repeat; width:654px; height:300px; cursor:pointer; } #site_dynamic_content2 { display:none; background-image:url(../images/man-on-camel.png); background-repeat:no-repeat; width:654px; height:300px; cursor:pointer; } Thanks for help! Quote Link to comment Share on other sites More sharing options...
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