function help

[will35010]

I have this function that calculates time between two timestamps. I want it to display days and subtract that time from the hours. Example output would be 2 Day(s) & 3 Hour(s) &  43 Minutes

 

Right now it displays the days, but it displays it like 7.33333. I don't want anything past the decimal point and it also doesn't take away from the hour count.

//function to calculate time duration using timestamps
function getTIME($time) {
//start/end dates
$startdate = $time;
$enddate = time();

//difference between the two in seconds
$time_period = ( $enddate - $startdate );

$minutes=floor($time_period/60); 
$hours=floor($minutes/60); 
$days=floor($hours/24);

if($hours>=24) {
    $daysdisplay = ($hours/24);
}
if($hours==1) { 
$hoursdisplay=$hours; 
} 
if(($minutes%60) > 1) { 
$minutesdisplay=($minutes%60); 
}
else if(($minutes%60)==1) { 
$minutesdisplay=($minutes%60);
} 
else { $minutesdisplay=""; 
} 
$display=$daysdisplay."Day(s)&  ".$hours."Hour(s) &  ".$minutesdisplay." Mins"; 

return $display;
}

[xangelo]

You're looking for this: http://ca.php.net/manual/en/function.round.php

[freeloader]

Doesn't really seem like a very efficient 'time ago' script.

 

You can find a few alternatives on this page:

http://php.net/manual/en/function.time.php

 

Search for 'ago'

 

This one seems to be pretty good though:

http://aidanlister.com/2004/04/making-time-periods-readable/

 

This would be a proper way of using it:

function getTIME($time) {
$convert = time( ) - $time;

return time_duration($convert);
}

 

You could also tweak your own script to fit for this, but I wouldn't really recommend it because it's rudementary. You'd need to round ( ) them to the nearest integer.

[will35010]

You're looking for this: http://ca.php.net/manual/en/function.round.php

 

Fixed that. Thanks!

 

updated code

//function to calculate time duration using timestamps
function getTIME($time) {
//start/end dates
$startdate = $time;
$enddate = time();

//difference between the two in seconds
$time_period = ( $enddate - $startdate );

$minutes=floor($time_period/60); 
$hours=floor($minutes/60); 
$days=floor($hours/24);

if($hours>=24) {
    $daysdisplay = round($hours/24);
}
if($hours==1) { 
$hoursdisplay=$hours; 
} 
if(($minutes%60) > 1) { 
$minutesdisplay=($minutes%60); 
}
else if(($minutes%60)==1) { 
$minutesdisplay=($minutes%60);
} 
else { $minutesdisplay=""; 
} 
$display=$daysdisplay."Day(s)&  ".$hours."Hour(s) &  ".$minutesdisplay." Mins"; 

return $display;
}

[will35010]

Doesn't really seem like a very efficient 'time ago' script.

 

You can find a few alternatives on this page:

http://php.net/manual/en/function.time.php

 

Search for 'ago'

 

This one seems to be pretty good though:

http://aidanlister.com/2004/04/making-time-periods-readable/

 

This would be a proper way of using it:

function getTIME($time) {
$convert = time( ) - $time;

return time_duration($convert);
}

 

You could also tweak your own script to fit for this, but I wouldn't really recommend it because it's rudementary. You'd need to round ( ) them to the nearest integer.

 

My script already does that.

[will35010]

Does anybody know how to modify my script? I'm not looking to replace my script. I want to change my script is all.

[freeloader]

Don't double post.

 

Just copy a pre-fixed script. I'm not going to waste my time if there are plenty of scripts out there that fit your needs.

[will35010]

Don't double post.

 

Just copy a pre-fixed script. I'm not going to waste my time if there are plenty of scripts out there that fit your needs.

 

I didn't double post.

 

Don't waste your time since you can't help anyway. If I wanted to replace it, I would have just ran to Google and copied someone's code. I wanted to fix my code so I could learn from it. Forgive me for trying to actually learn vs. copying someone's code that I didn't write.

[xangelo]

Is round() not working for you? It should have fixed your 7.3333 issue.

[will35010]

Is round() not working for you? It should have fixed your 7.3333 issue.

 

Yes. Round fixed the decimal point issue. But the issue that still remains is displaying in the format of my original post.