tsh9 Posted August 15, 2010 Share Posted August 15, 2010 Hello! I don't have a lot of experience wih PHP. I'm trying to make a page with two drop down list. The first one is a list of countries generated from an array. When the user selects a country a second drop down list is generated (dynamically) with a list cities from that country using an url: http://www.webservicex.net/globalweather.asmx/GetCitiesByCountry?CountryName=NP (where NP is the country name) and then get the weather info for the city from the selected country using: http://www.webservicex.net/globalweather.asmx/GetWeather?CityName=NV&CountryName=NP (Where NV is for the City name and NP the country name). I have a few problems 1. I would like to have the selected country/city stay the same even after submitting the request. 2. Have the weather information display after submitting the request. I have also included the files in a zip file. Any help would be greatly appreciated ! Thank you. <?php require("lib/util.lib.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="fr" lang="fr"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>La météo de la planète</title> <link rel="stylesheet" href="css/jqtransform.css" type="text/css" media="all" /> <link rel="stylesheet" href="css/style.css" type="text/css" media="all" /> <script src="http://www.google.com/jsapi" type="text/javascript"></script> <script type="text/javascript"> google.load("jquery", "1.3.2"); </script> <script type="text/javascript" src="js/jquery.jqtransform.js"></script> <script type="text/javascript" src="js/jquery.form.js"></script> <script type="text/javascript" src="js/websitechange.js"></script> </head> <body> <div id="page-wrap"> <h1>Weather around the world</h1> <form action="index.php" method="get" id="change-form"> <div class="rowElemSelect"> <label for="listCountry">Choose a country:</label> <select name="country"> <?php listePays(); ?> </select> <> <div class="rowElem"> <label> </label> <input type="submit" name="btnSubmitCountry" value="Submit" /> <> <div class="rowElemSelect"> <?php if(isset($_GET["btnSubmitCountry"]) && $_GET["country"] !=="") { $url = "http://www.webservicex.net/globalweather.asmx/GetCitiesByCountry?CountryName=".$_GET["country"]; $page = file_get_contents($url); $pattern = '/<City>(.*)<\/City>/'; preg_match_all($pattern, $page, $matches); echo '<label for="listCity">Choose a city:</label>'; echo '<select name="city">'; for($i=0; $i< count($matches[1]); $i++) { echo '<option value ="'.$matches[1][$i].'">'.$matches[1][$i].'</option>'; } echo '</select>'; echo '<div class="rowElem">'; echo '<label> </label>'; echo '<input type="submit" name="btnSubmitCity" value="Submit" />'; echo '<>'; } ?> <div class="rowElemSelect"> <?php if(isset($_GET["btnSubmitCity"]) && $_GET["country"] !=="" && $_GET["city"] !=="") { $url = "http://www.webservicex.net/globalweather.asmx/GetWeather?CityName=".$_GET['city']."NV&CountryName=".$_GET['country']; $page = file_get_contents($url); print_r($page); } ?> </form> <!--End page-wrap--> </body> </html> [attachment deleted by admin] Link to comment https://forums.phpfreaks.com/topic/210811-generating-a-drop-down-list-from-a-url-webservice/ Share on other sites More sharing options...
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