lasse48 Posted August 19, 2010 Share Posted August 19, 2010 hello guys , can you guys see any errors in this code`? i cant seem to find it :-\ <?php $units_stats_1 = array(40, 35, 50); $units_stats_2 = array($units_stats_1[0] * 50%, $units_stats_1[1] * 100%, $units_stats_1[2] * 100%); echo $units_stats_2; ?> i allso tryed to do : echo $units_stats_2[0]; thanks Link to comment https://forums.phpfreaks.com/topic/211151-php-array-with-help-request-p/ Share on other sites More sharing options...
MadTechie Posted August 19, 2010 Share Posted August 19, 2010 i assume you mean this, <?php $units_stats_1 = array(40, 35, 50); $units_stats_2 = array( $units_stats_1[0] * (1+(50/100)), $units_stats_1[1] * (1+(100/100)), $units_stats_1[2] * (1+(100/100))); echo $units_stats_2[0]."<BR />\n"; echo $units_stats_2[1]."<BR />\n"; echo $units_stats_2[2]."<BR />\n"; ?> remove the 1+ if you do mean (40 x 50%) that = 20 and the 35 and 50 would remain unchanged Link to comment https://forums.phpfreaks.com/topic/211151-php-array-with-help-request-p/#findComment-1101130 Share on other sites More sharing options...
lasse48 Posted August 19, 2010 Author Share Posted August 19, 2010 thanks alot MadTechie , it worked like i wanted it to do now with your help Link to comment https://forums.phpfreaks.com/topic/211151-php-array-with-help-request-p/#findComment-1101131 Share on other sites More sharing options...
MadTechie Posted August 19, 2010 Share Posted August 19, 2010 Your welcome, of course the 100/100 can be replaced with 1 (well 2 if you also remove the +1) i just added to make it clear.. if this is solved can you click solved (bottom left) --MadTechie Link to comment https://forums.phpfreaks.com/topic/211151-php-array-with-help-request-p/#findComment-1101134 Share on other sites More sharing options...
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