kool_samule Posted August 20, 2010 Share Posted August 20, 2010 Hi Chaps, I have a while loop which produces a couple of variables: do { $L_NAME.$i = 'Item 1'; $L_NUMBER.$i = '0001'; $L_QTY.$i = '1'; $L_AMT.$i = 10.50; $NVP.$i = "L_NAME.$i.= .$L_NAME.$i.&L_NUMBER.$i. = .$L_NUMBER.$i.&"; } while($i == $items); Basically what I need to do is contruct a parameter made up of all the $NVP variables. I've a feeling that I would need to add each variable to an array and then use a foreach statement, but I'm not 100% sure. I'd be interested in the correct way to go about this, any comments welcome! Link to comment https://forums.phpfreaks.com/topic/211261-construct-parameter-from-array/ Share on other sites More sharing options...
kool_samule Posted August 20, 2010 Author Share Posted August 20, 2010 $arr = array(); $L_NAME0 = 'Item 1'; $L_NUMBER0 = '0001'; $L_QTY0 = '1'; $L_AMT0 = 10.50; $NVP0 = "L_NAME0 = $L_NAME0&L_NUMBER0 = $L_NUMBER0&"; $arr[] = $NVP0; $L_NAME1 = 'Item 2'; $L_NUMBER1 = '0002'; $L_QTY1 = '3'; $L_AMT1 = 20.50; $NVP1 = "L_NAME1 = $L_NAME1&L_NUMBER1 = $L_NUMBER1&"; $arr[] = $NVP1; $joined_nvp = join("", $arr); echo $joined_nvp; Link to comment https://forums.phpfreaks.com/topic/211261-construct-parameter-from-array/#findComment-1101550 Share on other sites More sharing options...
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