mod_layout and include()

[bugscripts]

[I am asking this for someone else]
Say I want some PHP code executed on all pages in a certain directory.
If I add a PHP include() to the top of all pages with mod_layout, and have this in the included file test.php:
[code]<?php
echo $_SERVER['PHP_SELF'];
?>[/code]
On the page test.html (and all other pages, just an example) I get this printed:
[quote]/test.php[/quote]
I want this printed:
[quote]/test.html[/quote]
Thanks for any help! :)

[tomfmason]

I can think of a couple ways that you can do this. You could ether use preg_replace or an explode function. Here is an example of explode.

[code=php:0]
$p = $_SERVER['PHP_SELF'];
list($page, $ext) = explode(".", $p);
echo $page . '.html';
[/code]

This may not be the most efficent way of doing this but it will work.

Hope this helps,
Tom

[bugscripts]

That's not exactly what I meant. I want it to determine the name of the page mod_layout is including it into, but instead it is giving me the name of the script that is supposed to determine it.

Sorry if I am not making any sense  :)

[steveclondon]

Hi,

Just use this. Please note that it doesn't work on a windows server only apache.

<?php
echo $_SERVER['REQUEST_URI'];
?>

[bugscripts]

That doesn't work, and the other methods of printing the URL that I know of do the same thing.

I tested it with a regular include(), and it works as expected.