Jump to content

Help for PHP, MySQL and AJAX


deemi_pk

Recommended Posts

Hi how r u. i hope u all r fine i need some help,

 

i creat a company table there is comp_name; comp_adres; comp_country; comp_city.

 

i creat an ajax file that when i chose country their related city come cities come successfully but when i want save it all data save in mysql else city i dont know what to do i past my script so please help me.

 

Country Table

CREATE TABLE IF NOT EXISTS `tbl_country` (
  `cont_id` int(11) NOT NULL AUTO_INCREMENT,
  `cont_name` varchar(100) NOT NULL,
  PRIMARY KEY (`cont_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=6 ;

--
-- Dumping data for table `tbl_country`
--

INSERT INTO `tbl_country` (`cont_id`, `cont_name`) VALUES
(2, 'Pakistan'),
(4, 'Saudi Arabia'),
(5, 'Spain');

 

City Table

CREATE TABLE IF NOT EXISTS `tbl_city` (
  `city_id` int(11) NOT NULL AUTO_INCREMENT,
  `city_name` varchar(100) NOT NULL,
  `city_country` int(11) NOT NULL,
  PRIMARY KEY (`city_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=24 ;

--
-- Dumping data for table `tbl_city`
--

INSERT INTO `tbl_city` (`city_id`, `city_name`, `city_country`) VALUES
(1, 'Islamabad', 2),
(2, 'Lahore', 2),
(3, 'Karachi', 2),
(4, 'Peshawar', 2),
(5, 'Quetta', 2),
(6, 'Riyadh', 4),
(7, 'Gujranwala', 2),
(8, 'Jaddah', 4),
(9, 'Makkah', 4),
(10, 'Madinah', 4),
(12, 'Faisalabad', 2),
(17, 'Hyderabad', 2),
(18, 'Madrid', 5),
(19, 'Cordoba', 5),
(22, 'Granada', 5),
(23, 'Toledo', 5);

 

Company Table

CREATE TABLE IF NOT EXISTS `tbl_company` (
  `comp_id` int(11) NOT NULL AUTO_INCREMENT,
  `comp_name` varchar(100) NOT NULL,
  `comp_adres` varchar(100) NOT NULL,
  `comp_country` int(11) NOT NULL,
  `comp_city` int(11) NOT NULL,
  PRIMARY KEY (`comp_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=18 ;

--
-- Dumping data for table `tbl_company`
--

INSERT INTO `tbl_company` (`comp_id`, `comp_name`, `comp_adres`, `comp_country`, `comp_city`) VALUES
(1, 'Interactive Production', 'Trust Plaza 70-B', 2, 2),
(3, 'PMS', 'Model Town', 2, 7),
(7, 'im Logic', 'ByPass', 2, 3),
(8, 'Young Spiders', 'Hall Road', 5, 19),
(9, 'JJ', 'Gill Road', 4, 0),
(15, 'df', 'dfgg', 2, 0),
(16, 'df', 'dfgg', 2, 0),
(17, 'sdfsdf', 'sdfsdf', 4, 0);

 

Ajax File with HTML

<script type="text/javascript" language="javascript">

function showCountry(str)
	{
		if (str=="")
  				{
  					document.getElementById("txtHint").innerHTML="";
  					return;
  				} 
		if (window.XMLHttpRequest)
  			{// code for IE7+, Firefox, Chrome, Opera, Safari
  					xmlhttp=new XMLHttpRequest();
  				}
		else
  				{// code for IE6, IE5
  					xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  				}
				xmlhttp.onreadystatechange=function()
  				{
  					if (xmlhttp.readyState==4 && xmlhttp.status==200)
    			{
    				document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","getCity.php?q="+str,true);
xmlhttp.send();
	}

</script>
<table width="100%" border="0" cellspacing="2" cellpadding="2" align="center">
              	<tr>
                	<td colspan="2" class="heading" align="center">Add Company</td>
              	</tr>
               <tr>
                	<td> </td>
              	</tr>
              	<tr>
                	<td class="loginText">Company Name :</td>
                	<td>
				<input type="text" name="txtCompname" id="txtCompname" maxlength="70" size="40" style="padding-left:6px;" />
                  </td>
              	</tr>
               <tr>
                	<td class="loginText">Company Address :</td>
                	<td>
				<input type="text" name="txtCompadres" id="txtCompadres" maxlength="100" size="40" style="padding-left:6px;" />
                  </td>
              	</tr>
               <tr>
                	<td class="loginText">Select Country :</td>
                	<td>
                  <select name="selectCountry" id="selectCountry" onchange="showCountry(this.value)">
   							<option value="0"> >--- Select Country ---< </option>
							<?php
                           $id = 'Select * From tbl_country';
                           $qry = mysql_query($id);
                           echo mysql_num_rows($qry);
                           while($row = mysql_fetch_array($qry))
                              {
                        ?>
      						<option value="<?php echo $row['cont_id']; ?>"> <?php echo $row['cont_name']; ?></option>
      						<?php } ?>
   					</select>
                  </td>
              	</tr>
               <tr>
                	<td class="loginText">Select City :</td>
                	<td><div id="txtHint">City</div></td>
              	</tr>
              	<tr>
                	<td> </td>
                	<td> </td>
              	</tr>
              	<tr>
                	<td colspan="2" class="submit" align="right">
  <input type="submit" name="subComp" id="subComp" value="Save Company" style="margin-right:32px;" />
                  </td>
              	</tr>
            </table>

 

getCity.php

<?php

require('db.php');

$q = intval($_GET['q']);

?>
<form name="frmCity" id="frmCity" method="post" action="addCompany.php">

<select name="selCity" id="selCity">
   	<option value="0"> >--- Select City ---< </option>
   	<?php
$id = 'Select * From tbl_city Where city_country='.$q;
$qry = mysql_query($id);
while($row = mysql_fetch_array($qry))
	{
?>
      <option value="<?php echo $row['city_id']; ?>"><?php echo $row['city_name']; ?></option>
      <?php } ?>
   </select>

</form>

 

Please Help me and tell me wat can i do and where can i put

 

Link to comment
https://forums.phpfreaks.com/topic/212142-help-for-php-mysql-and-ajax/
Share on other sites

Archived

This topic is now archived and is closed to further replies.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.