deansaddigh Posted September 3, 2010 Share Posted September 3, 2010 I need to invoc the code below but have no idea on how to it. Can anyone help Invocation code Prepare a block level element with some images inside. All you have to do is to select the elements in a jQuery way and call the plugin. $('#myGallery').spacegallery({loadingClass: 'loading'}); Quote Link to comment Share on other sites More sharing options...
dgoosens Posted September 3, 2010 Share Posted September 3, 2010 well you need to create a div (or other type of block) with the ID and put an image in it... <div id="myGallery"> <img src="/path/to/som/image.png" alt="some image"> </div> and you should make a JavaScript call to the function they indicate <script type="text/javascript"> $(function(){ $('#myGallery').spacegallery({loadingClass: 'loading'}); } </script> or something like that... (not easy with the little info you supply) Quote Link to comment Share on other sites More sharing options...
deansaddigh Posted September 3, 2010 Author Share Posted September 3, 2010 Hey thanks for the reply, i have done all that, as thats what i thought i was meant to do , it still doesnt work at all. this tells you how to implement it. http://www.eyecon.ro/spacegallery/#implement And i have done exactly that to no avail what so ever heres my sections of code. <link href="/style.css" rel="stylesheet" type="text/css" media="screen" /> <link rel="stylesheet" media="screen" type="text/css" href="/css/spacegallery.css" /> <link rel="stylesheet" media="screen" type="text/css" href="/css/custom.css" /> <script type="text/javascript" src="/js/jquery.js"></script> <script type="text/javascript" src="/js/eye.js"></script> <script type="text/javascript" src="/js/utils.js"></script> <script type="text/javascript" src="/js/spacegallery.js"></script> <script type="text/javascript" src="/js/layout.js"></script> <script type="text/javascript"> $(function(){ $('#myGallery').spacegallery({loadingClass: 'loading'}); } </script> echo '<div id="myGallery" class="spacegallery">'; while($copiedrow = mysql_fetch_array($copiedresult)) { $imagename = $copiedrow ['image_name']; $image = '/admin/'.$copiedrow['path'] . '/' . $copiedrow ['image_name']; // echo '<a href="'.$image.'" rel="shadowbox" title="'.$imagename.'" class="floatright"><img src="'.$image.'" width="150" height="150"/></a>'; echo '<img src="'.$image.'" alt="" />'; } echo '</div>'; Any help would be brilliant because i have been trying to implement this since 8 oclock last night Kind regards Oh also heres the link to my page where its supposed to work. http://www.languageschoolsuk.com/school_details/Kings_Colleges_Bournemouth Dean Quote Link to comment Share on other sites More sharing options...
deansaddigh Posted September 3, 2010 Author Share Posted September 3, 2010 Its ok i have done it Kind regards Dean Quote Link to comment Share on other sites More sharing options...
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