princevnyt Posted September 30, 2010 Share Posted September 30, 2010 Hi! I need help with the login script i wrote. Please help me get it working. The section related to guest works fine however it always gives me error message when i get to the queryA and queryB stages. Thanks! I've already got the database running, using MySQL. Name of database - connectiontracker; tables- user_admin, user_user Here's the script: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/xhtml1-loose.dtd"> <?php session_start(); $userType = $_POST["userType"]; $userName = $_POST["username"]; $passWord = $_POST["password"]; $link = mysqli_connect("localhost", "ct1", "ctcfgb") Or die('Could not connect '. mysqli_error()); switch ($userType) { case "admin": if (isset($userName) && isset($passWord)) { $dbTableA = "user_admin"; mysqli_select_db($link, "connectiontracker") Or die ("Database unavailable"); $queryA = "SELECT * FROM $dbTableA WHERE username='$userName' AND password='$passWord'"; $resultA = mysqli_query($queryA) or die("Verification Error A"); if(mysqli_num_rows($resultA) == 1) { $_SESSION = true; header ('Location: welcomeadmin.php'); } else echo "Incorrect administrator username and/or password"; } break; case "user": if (isset($userName) && isset($passWord)) { $dbTableB = "user_user"; mysqli_select_db($link, "connectiontracker") Or die ("Database unavailable"); $queryB = "SELECT * FROM $dbTableB WHERE username='$userName' AND password='$passWord'"; $resultB = mysqli_query($queryB) or die("Verification Error B"); if(mysqli_num_rows($resultB) == 1) { $_SESSION = true; header ('Location: welcomeuser.php'); } else echo "Incorrect Organization/Individual username and/or password"; } break; case "guest": header ('Location: welcomeguest.php'); break; } if (!isset($_POST['Enter'])) { ?> <html> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8"> <title>Login to Connection Tracker</title> <!-- <link rel="stylesheet" href="ct_style1.css" type="text/css"> --> </head> <body> Please select from the following: <br /> <form action="<?php echo $PHP_SELF;?>" method="post"> <select name="userType"> <option value="admin">Administrator</option> <option value="user" selected>Organization</option> <option value="guest">Guest</option> </select> <br /> Please leave the following fields blank if entering the system as Guest <br /> Username: <input type="text" name="username"> <br /> Password: <input type="text" name="password"> <input type="submit" name="Enter"/> <br /> </form> </body> </html> <?php } mysqli_close($link); ?> Quote Link to comment https://forums.phpfreaks.com/topic/214843-login-script-need-help/ Share on other sites More sharing options...
Psycho Posted September 30, 2010 Share Posted September 30, 2010 Let me pull out my crystal ball so I can see what the error messages are ... that might take a while. You could just tell us what the error messages are. Quote Link to comment https://forums.phpfreaks.com/topic/214843-login-script-need-help/#findComment-1117661 Share on other sites More sharing options...
princevnyt Posted September 30, 2010 Author Share Posted September 30, 2010 Verification Error A or Verification Error B Also, I do select the database, inside the case statements the problem is that i can't seem to make my program extract the username and password and enter them into the sql query! Quote Link to comment https://forums.phpfreaks.com/topic/214843-login-script-need-help/#findComment-1117664 Share on other sites More sharing options...
mikosiko Posted September 30, 2010 Share Posted September 30, 2010 a simple way to see what is happening... change this: die("Verification Error A"); // or the other to this die("Verification Error A <br />" . $queryA . "<br />" . mysql_error()); it should allow you to see the query that you are trying to execute and the associated error... after that you should be able to fix it Quote Link to comment https://forums.phpfreaks.com/topic/214843-login-script-need-help/#findComment-1117689 Share on other sites More sharing options...
PFMaBiSmAd Posted September 30, 2010 Share Posted September 30, 2010 mysqli_query() requires two parameters. There are php errors that would be notifying you of that problem. You should be developing and debugging your code on a system with error_reporting set to E_ALL and display_errors set to ON so that all the php errors would be reported and displayed. You will save a ton of time with these simple coding errors. Quote Link to comment https://forums.phpfreaks.com/topic/214843-login-script-need-help/#findComment-1117692 Share on other sites More sharing options...
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