Unbale to use shell_exec

[theface]

When i try to do a shell_exec from my script the script does not work.

But when i put the same thing in a .bat file and execute that from PHP it wroks.

 

Can anyone help me

shell_exec('xcopy C:\xampp\htdocs\test\backup\test.zip "\\fileserver\KT_backup\aback\" /i')  

[jammesz]

As i haven't used any windows past xp and i dont know which version you have i cant really help.

I personally use linux and for me shell_exec needs a bit more info to work.

Example:

shell_exec("DISPLAY=:0 sudo -u username firefox ".$url);

 

Now i know this will not work for you as your on windows but you should research the function a bit more and try and get some insight into what the function may need/require in order for it to work.

 

On the other hand maybe on windows you don't need to do anything and it's just the command itself thats the problem.

[theface]

I am using Windows Vista. when i do

shell_exec('dir > dir.txt'); 

it works and creates a text file with the dir output. Probably its the syntax problem.

[jammesz]

In that case, yes, i think its the command and not the function thats not working.

[theface]

as i said before the command is ok when i run it from a bat file

[jammesz]

what i really meant was, as you said before, that its probably a syntax error in the command.

[phpchamps]

i am not sure whether this can help or not:  but your problem seems to be similar (command working from batch file or command line and not through shell_exec).

 

I found out that in my case some things needed to be set (which normally are set by default).

 

the options -jo

-j means: don't recreate the paths found in the archive

-o means: always overwrite files

 

And I needed to specify the destination path (even though it should unzip in the same directory when not specified), this is done by -d [path]

 

The strange thing was that I didn't have to put these options when I would give the command on the command-line, only when I would call it with shell_exec.

 

So the complete command in php would be for me:

 

shell_exec('unzip -jo /path_to_archive/archive.zip  -d /destination_path')

 

And putting en echo in front will help you a lot.

it should tell you something like this:

   

 

Archive:  /path_to_zip/archive.zip

  inflating: /destination_path/file1.jpeg

  inflating: /destination_path/file2.jpeg

  inflating: /destination_path/file3.jpeg