Vars within function made global but not displaying..?

[AbydosGater]

Hi ok well first the background, the function is within my config file which is included within the file i am having problems with, and the page i have another function already running to connect to the database,

Now here is the code to my function...
[code]
function pagenav(){

if (isset($_GET['id'])) {
$result = mysql_query("SELECT * FROM ben_pages WHERE id='$_GET[id]'") or die(mysql_error()); 
$row = mysql_fetch_array( $result );
$pagetitle = $row['title'];
$pagecontent = $row['page'];
//echo $pagetitle ;
//echo "<br />";
//echo $pagecontent ;
}
else {
$result = mysql_query("SELECT * FROM ben_pages WHERE id='index'") or die(mysql_error()); 
$row = mysql_fetch_array( $result );
$pagetitle = $row['title'];
$pagecontent = $row['page'];
global $pagetitle, $pagecontent;
//echo $pagetitle;
//echo "<br />";
//echo $pagecontent;
};
};
[/code]

Now if i uncomment the echos there, I do get the variables to display!, But i have that function running on another page, but i have the page displaying $pagetitle , $pagecontent at another point outside the function, but it isnt displaying, how come? i have them set to global?
anyone any ideas?, any help atall would be great?

Thanks

[shoz]

Declare the variables global before assigning them values.
[code]
global $pagetitle, $pagecontent;
[/code]
http://www.php.net/manual/en/language.variables.scope.php

I'd recommend you simply return an array with the relevant information rather than setting them global.

[code]
function pageNav()
{
  $pageData['title'] = $row[..]
  $pageData['content'] = $row[...];
 
  return $pageData;
}

$pageData = pageNav();
echo $pageData['title']."<br />\n";
echo $pageData['content']."<br />\n";
[/code]

[AbydosGater]

ehh, im not that good and dont really understand that :P

[shoz]

[quote author=AbydosGater link=topic=108934.msg438807#msg438807 date=1158857110]
ehh, im not that good and dont really understand that :P
[/quote]
[code]
function add($a, $b)
{
  $total = $a +$b;
  return $total;
 
  //"return $a + $b" would also achieve the same result.
}
$aVarl = add(5, 1);
print $aVar //Prints "6"
[/code]
http://www.php.net/manual/en/functions.returning-values.php

[AbydosGater]

Ah ok yeah i get it now! Thanks its all working now!