Get value that has... unless...

[The Little Guy]

I currently have this line, which gets me all the links on a page.

 

preg_match_all("~<a.+(href=\"(.+?)\")~i", $this->data, $arr);

 

How can NOT include links in the array that contain the word javascript: at the beginning?

[Anti-Moronic]

I don't know of a way to do this *during* a regex, but you could simply iterate over your matches later and filter out those that include javascript.

foreach($arr as $key => $element){
  if(preg_match("#javascript#", $element)){
    unset($arr[$key]);
  }
}

 

I'd love to know if this is possible during a capture.

 

EDIT: actually, my regex above won't do because a url could contain javascript as a url to a page. You would have to amend to include : - and, from what I can tell, your regex will not match against urls which use ' to enclose the href.

[mattal999]

Could just do this:

 

foreach($arr as $key => $element) {
  if(stripos($element, "javascript:")) { // Or use strpos(strtolower($element), "javascript:") for PHP4
    unset($arr[$key]);
  }
}

[salathe]

Firstly, parsing HTML documents with regex is a really hacky way of doing things. There are tools dedicated to making sense out of (HT|X)ML documents built in to PHP, like DOM.

 

Secondly, you can use a "negative lookahead" within your regular expression to assert that javascript: doesn't appear where you don't want it:

 

~<a.+(href="(?!javascript:)(.+?)")~i