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$sql = 'SELECT * FROM account_info WHERE username ="'.$name.'"';
$result = mysql_query($sql) . mysql_error();
$row = mysql_fetch_row($result);

 

I get

 

Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource

 

I'm trying to output the row "wins" for a certain user.

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https://forums.phpfreaks.com/topic/217957-why-wont-this-work-seems-simple-enough/
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$result = mysql_query($sql) . mysql_error();

 

^^^ By concatenating msyql_error() with the result of the mysql_query() in the above line of code, you are likely corrupting the value being put into $result.

 

That line of code should be as follows to get it to display the mysql_error() value if the query fails -

 

$result = mysql_query($sql) or die(mysql_error());

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