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ok

 

I\'ve spent the better part of.... all day coding some PHP pages for my project (Private Messaging System.. Inbox and Send Private Message..... each are bout 150 or 200+ lines of code)

 

brain... fried....

need extra pair of eyes to debug

 

error

Warning: Supplied argument is not a valid MySQL result resource in c:apachehtdocs3kphpInbox.php on line 40

 

block of code with error

[php:1:decfc04bb6]

while($pmnum = mysql_fetch_array($result)){ //line 40

if(mysql_num_rows($result) == 0) {

echo(\"You don\'t have any Messages\");

} else {

print(\"<TR><TD WIDTH=\'25%\'>\");

echo $pmnum[from];

print(\"</TD> <TD WIDTH=\'50%\'>\");

echo $pmnum[subject];

print(\"</TD> <TD WIDTH=\'25%\'>\");

echo $pmnum[sent];

print(\"</td></TR>\");

}

}

[/php:1:decfc04bb6]

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your query ( not listed ) didn\'t return any results...  :shock: does it work if you ad hoc it? any syntax errors?

 

thats the only error I got....

 

didn\'t think about adding some rows to the database to see if it actually works

 

I\'m gonna try that

 

that is what your sayin right?

 

edit...

now I got that same error on line 15 as well as the above posted error

 

[php:1:fd6390f548]

$limit = 15;

$messages = \"SELECT users FROM messages WHERE to=\'$username\'\";

$getmessages = mysql_query($messages);

$pmnum = mysql_num_rows($getmessages); //line 15

[/php:1:fd6390f548]

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I guess the problem is either with ur connection string or ur query

 

Try to run the query seperately and see whether u get any values.

 

$link = mysql_connect(\"localhost\", \"username\", \"password\");

mysql_select_db(\"database\", $link);

 

 


mysql_query($messages) or die("problem here ");

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https://forums.phpfreaks.com/topic/218-not-valid-sql/#findComment-700
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uhh

 

ok

this makes no sense

 

I got a 500 Internal Server Error

 

I have no idea whats goin on

 

edit: nevermind

the error is gone

however...

my old error remains

 

ok

this makes a lot of sense

I remove the or die(); part and it works fine

 

edit

ok

I added more of the code and I have that same error

 

Warning: Supplied argument is not a valid MySQL result resource in c:apachehtdocsmysqlqtest.php on line 7

 

[php:1:ac080681c1]

$messages = \"SELECT users FROM messages\";

$getmessages = mysql_query($messages);

$pmnum = mysql_num_rows($getmessages); // line 7

[/php:1:ac080681c1]

 

what exactly is goin on?

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https://forums.phpfreaks.com/topic/218-not-valid-sql/#findComment-701
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