Warning: mysqli_error() expects exactly 1 parameter, 0 given in

[genzedu777]

Hi guys,

 

I have an error msg here, "Warning: mysqli_error() expects exactly 1 parameter, 0 given in D:\inetpub\vhosts\championtutor.com\httpdocs\tutor_registration3.php on line 598". I have highlighted the error line in red, do you guys have any idea what went wrong? Thanks

 

<?php

$dbc = mysqli_connect('localhost', '111', '111', '111')

or die(mysqli_error());

$query = "SELECT sl.subject_level_id, sl.level_id, sl.subject_id, tl.name AS level_name, ts.name AS subject_name " .

    "FROM tutor_subject_level AS sl " .

    "INNER JOIN tutor_level AS tl USING (level_id) " .

    "INNER JOIN tutor_subject AS ts USING (subject_id) ";

$sql = mysqli_query($dbc, $query)

or die(mysqli_error());

 

echo'<table><tr>'; // Start your table outside the loop... and your first row

$count = 0; // Start your counter

while($data = mysqli_fetch_array($sql)) {

/* Check to see whether or not this is a *new* row

If it is, then end the previous and start the next and restart the counter.

*/

if ($count % 5 == 0) {

echo "</tr><tr>"; $count = 0;

}

echo '<td><input name="subject_level[]" type="checkbox" id="'.$data['subject_level_id'].'" value="'.$data['subject_level_id'].'"/>';

echo '<label for="'.$data['subject_name'].'">'.$data['subject_name'].'</label></td>';

$count++; //Increment the count

}

echo '</tr></table><br/><br/>'; //Close your last row and your table, outside the loop

 

?>

[PFMaBiSmAd]

I recommend you read the php.net documentation for mysqli_error(), it requires the mysqli link as a parameter.

[genzedu777]

Hi PFMaBiSmAd,

 

Thanks for the info, I've read it, but I still don't quite understand what they mean, just to check with you, does php has any software to debug?

 

Thanks,

Wilson