Jump to content

Trying to code a Joomla Search plugin.


lukejd83

Recommended Posts

Hi all!  I have racked my brain trying to figure this one out.  I'm typically a smart cookie, but since I am new to php and mysql, I'm stumped.  I'm just trying to program a Joomla search plugin that queries my HDFLV player database, so videos are searchable, but I keep getting an invalid "foreach(" command.  It's supposed to be there to interpret the database query, right?

 

I'll post my code here, can someone give me some insight?

 


<?php
/**
* @version		$Id: contacts.php 10381 2008-06-01 03:35:53Z pasamio $
* @package		Joomla
* @copyright	Copyright (C) 2005 - 2008 Open Source Matters. All rights reserved.
* @license		GNU/GPL, see LICENSE.php
* Joomla! is free software. This version may have been modified pursuant
* to the GNU General Public License, and as distributed it includes or
* is derivative of works licensed under the GNU General Public License or
* other free or open source software licenses.
* See COPYRIGHT.php for copyright notices and details.
*/

// no direct access
defined( '_JEXEC' ) or die( 'Restricted access' );

$mainframe->registerEvent( 'onSearch', 'plgSearchhdflvplayer' );
$mainframe->registerEvent( 'onSearchAreas', 'plgSearchhdflvplayerAreas' );

JPlugin::loadLanguage( 'plg_search_hdflvplayer' );

/**
* @return array An array of search areas
*/
function &plgSearchhdflvplayerAreas()
{
static $areas = array(
	'hdflvplayer' => 'Videos'
);
return $areas;
}

/**
* Contacts Search method
*
* The sql must return the following fields that are used in a common display
* routine: href, title, section, created, text, browsernav
* @param string Target search string
* @param string mathcing option, exact|any|all
* @param string ordering option, newest|oldest|popular|alpha|category
*/
function plgSearchhdflvplayer( $text, $phrase='', $ordering='', $areas=null )
{
$db		=& JFactory::getDBO();
$user	=& JFactory::getUser();

if (is_array( $areas )) {
	if (!array_intersect( $areas, array_keys( plgSearchhdflvplayerAreas() ) )) {
		return array();
	}
}

// load plugin params info
	$plugin =& JPluginHelper::getPlugin('search', 'hdflvplayer');
	$pluginParams = new JParameter( $plugin->params );

$limit = $pluginParams->def( 'search_limit', 50 );

$text = trim( $text );
if ($text == '') {
	return array();
}

$section = JText::_( 'hdflvplayer' );

switch ( $ordering )
{
	case 'oldest':
		$order = 'a.id ASC';
		break;

	case 'popular':
		$order = 'a.times_viewed DESC';
		break;

	case 'alpha':
		$order = 'a.title ASC';
		break;

	case 'category':
		$order = 'b.title ASC, a.title ASC';
		break;

	case 'newest':
	default:
		$order = 'a.id DESC';
}

$text	= $db->Quote( '%'.$db->getEscaped( $text, true ).'%', false );
$query	= 'SELECT a.title AS title, "" AS created,'
. ' CASE WHEN CHAR_LENGTH(a.alias) THEN CONCAT_WS(\':\', a.id, a.alias) ELSE a.id END as slug, '
. ' CASE WHEN CHAR_LENGTH(b.alias) THEN CONCAT_WS(\':\', b.id, b.alias) ELSE b.id END AS catslug, '
. ' CONCAT_WS( ", ", a.title, a.description ) AS text,'
. ' CONCAT_WS( " / ", '.$db->Quote($section).', b.title ) AS section,'
. ' "2" AS browsernav'
. ' FROM #__hdflvplayerupload AS a'
. ' INNER JOIN #__hdflvplayername AS b ON b.id = a.catid'
. ' WHERE ( a.title LIKE '.$text
. ' OR a.description LIKE '.$text.' )'
. ' AND a.published = 1'
. ' AND b.published = 1'
. ' AND a.access <= '.(int) $user->get( 'aid' )
. ' AND b.access <= '.(int) $user->get( 'aid' )
. ' GROUP BY a.id'
. ' ORDER BY '. $order
;
$db->setQuery( $query, 0, $limit );
$rows = $db->loadObjectList();

foreach($rows as $key => $row) {
	$rows[$key]->href = '?pid='.$row->slug;
}

return $rows;
}


 

 

ANY help is more than what I got from HDFLV Player support.

 

Thank you so much in advance!

 

[attachment deleted by admin]

Link to comment
https://forums.phpfreaks.com/topic/218895-trying-to-code-a-joomla-search-plugin/
Share on other sites

what's the exact error? If it's related to the foreach, most likely it's because $rows isn't an array. You'll get an array if you try to pass something other than an array to a foreach loop. I would print your query to the browser, then try to run it directly in mySQL to see if the query is failing (which is one reason why $rows wouldn't be an array)

Archived

This topic is now archived and is closed to further replies.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.