Calling class when class name is build from variables.

[the_oliver]

Hi,

 

I need to be able to call a class based on variables.  E.G.

 

I would normally do:

$action = new pattern1()

 

but i would like to be able to do it dynamicaly:

$patNum = 1;
$action = new pattern.$patNum.()

 

Im wondering if that's possible?  If so what would the correct syntax be?

 

Many Thanks.

[MrXHellboy]

I guess concatenation will not work with instances. You can create 2 separate methods and use a if construct to call the methods.

[GKWelding]

If I remember rightly, this will work...

 

$className = 'pattern'.$patNum;

$action = new $className();