Date sheet population

ankycooper · September 25, 2006

hi i have a database in which there are following fields
name
month
startdate
enddate
starttime
endtime
wf1
wf2
wf3

lets take a sample data
jay peter
march
2006-09-03
2006-09-24
07:00
16:00
Saturday
Sunday
NA

there are sevral such records

i want to populate a table like this (see the attachment)

Need some help

[attachment deleted by admin]

steveclondon · September 25, 2006

Do you mean export to excel or just display in the browser in a table.

ankycooper · September 25, 2006

Populate as a table in the browser

Please Help

Barand · September 25, 2006

You just need to output 2 HTML table rows for each record in the db table
[code]
<tr><td rowspan='2'>$date</td> <td rowspan='2'>$day</td> <td>Office reporting</td> <td>$time1</td></tr>
<tr> <td>Office departing</td> <td>$time2</td></tr>
[/code]

craygo · September 25, 2006

Try this
[code]<table width=800 align=center border=1>
<tr>
<td width=150>Date</td>
<td width=150>Day</td>
<td width=300>Time</td>
<?php
$sql = "SELECT * FROM table_name";
$res = mysql_query($sql) or die (mysql_error());
$r = mysql_fetch_assoc($res);
echo "<td width=200>".$r['name']."</td></tr>";
$days = (date("j", strtotime($r['enddate'])) - date("j", strtotime($r['startdate']))) + 1;
$startdate = date("Y-m-d", strtotime($r['startdate']));
for($i=0; $i<$days; $i++){
$day = date("D", strtotime($startdate));
$fullday = date ("l", strtotime($startdate));
if($fullday == $r['wf1'] || $fullday == $r['wf2'] || $fullday == $r['wf3']){
$st_time = "WOFF";
$e_time = "WOFF";
} else {
$st_time = $r['starttime'];
$e_time = $r['endtime'];
}
echo "<tr>";
echo "<td rowspan=2>$startdate</td>";
echo "<td rowspan=2>$day</td>";
echo "<td>Start time</td>";
echo "<td>$st_time</td>";
echo "</tr>";
echo "<tr>";
echo "<td>End Time</td>";
echo "<td>$e_time</td>";
echo "</tr>";
$startdate = date("Y-m-d", strtotime("$startdate +1 day"));
}
echo "</table>";
?>[/code]

Ray

ankycooper · September 25, 2006

Still No Good

Does Any one Knows How To Do It

craygo · September 25, 2006

Works fine for me based on your info up top.

Ray

ankycooper · September 27, 2006

This Code Works For ME But it only shows the 1st record and does not populate all of them

[code]<html>
<link rel="stylesheet" type="text/css" href="../scripts/main.css" >
<head>
<title>Roster Management System</title>
</head>

<body bgcolor="#C7E1F4">
<div align="center">
<center>

<table border="0" cellpadding="0" cellspacing="0" style="border-collapse: collapse" bordercolor="#111111" bgcolor="#EEEEEE">
<tr style="font-size: 12px; color: #ffffff; font-family: Arial, Helvetica, sans-serif">

<td class="info" style='border:1px solid #C7E1F4; background-color: #2955B5' width="100" height="1">
 Date  </td>
<td class="info" style="border:1px solid #C7E1F4; background-color: #2955B5" width="65" height="1">
 Day  </td>
<td class="info" style="border:1px solid #C7E1F4; background-color: #2955B5" width="100" height="1">
 Time  </td>

<?php
function dateconvert($date,$func) {
if ($func == 1){ //insert conversion
list($day, $month, $year) = split('[/.-]', $date);
$date = "$year-$month-$day";
return $date;
}
if ($func == 2){ //output conversion
list($year, $month, $day) = split('[-.]', $date);
$date = "$day/$month/$year";
return $date;
}
}

$mmyy=$_GET['mmyy'];

include '../config/dbinfo.inc.php';
@mysql_connect($host,$user_name,$pass_word);
@mysql_select_db($database) or die( "Unable to select database");
$sql = "SELECT * FROM emproster where mmyy='$mmyy'";
$sql = "SELECT * FROM emproster where mmyy='$mmyy'";
$res = mysql_query($sql) or die (mysql_error());
$r = mysql_fetch_assoc($res);
echo "<td class='info' style='border:1px solid #C7E1F4; background-color: #2955B5' width='150' height='1'>
 ".$r['name']."</td>";
echo "</tr>";
$days = (date("j", strtotime($r['edate'])) - date("j", strtotime($r['sdate']))) + 1;
$sdate = date("Y-m-d", strtotime($r['sdate']));
for($i=0; $i<$days; $i++){
$day = date("D", strtotime($sdate));
$fullday = date ("l", strtotime($sdate));
if($fullday == $r['wf1'])
{
$st_time = "             WOFF             ";
$e_time = "             WOFF             ";
}

elseif($fullday == $r['wf2'])
{
$st_time = "             WOFF             ";
$e_time = "             WOFF             ";
}
elseif($fullday == $r['wf3']){
$st_time = "             WOFF             ";
$e_time = "             WOFF             ";
}
else {

$st_time = "              ".$r['stime']."              ";
$e_time = "              ".$r['etime']."              ";
}
$sdate=dateconvert($sdate, 1);
echo "<tr>";

echo "<td class='back2' style='border:1px solid #C7E1F4; background-color: #CED7EF' rowspan=2> $sdate</td>";
echo "<td class='back2' style='border:1px solid #C7E1F4; background-color: #CED7EF' rowspan=2> $day</td>";
echo "<td class='back2' style='border:1px solid #C7E1F4; background-color: #CED7EF'> Report Time</td>";
echo "<td class='back2' style='border:1px solid #C7E1F4; background-color: #CED7EF'>$st_time</td>";
echo "</tr>";
echo "<tr>";

echo "<td class='back2' style='border:1px solid #C7E1F4; background-color: #CED7EF'> Drop Time</td>";
echo "<td class='back2' style='border:1px solid #C7E1F4; background-color: #CED7EF'>$e_time</td>";
echo "</tr>";
$sdate = date("Y-m-d", strtotime("$sdate +1 day"));
}
echo "</table>";
?>

</center></div>[/code]

ankycooper · October 1, 2006

Please Help

ankycooper · October 1, 2006

I Think no one is a real Guru Who can solve this

Sign In

Date sheet population

Recommended Posts

ankycooper

Link to comment

Share on other sites

steveclondon

Link to comment

Share on other sites

ankycooper

Link to comment

Share on other sites

Barand

Link to comment

Share on other sites

craygo

Link to comment

Share on other sites

ankycooper

Link to comment

Share on other sites

craygo

Link to comment

Share on other sites

ankycooper

Link to comment

Share on other sites

ankycooper

Link to comment

Share on other sites

ankycooper

Link to comment

Share on other sites

Archived

Browse

Activity

Important Information