mlummus Posted November 27, 2010 Share Posted November 27, 2010 I'm trying to create a table form that pulls in "Extra" choices from a table and allows users to select a number of days and number of guests for each choice. I started creating it a a checkbox field but am thinking just using the name as a label and setting days and guests to default "0" might be a better bet. Guidance from someone more experienced with this? Also, how do I store the submission (db structure - in the "reservations" table, another?). I'm new to this and feel kind of lost with this challenge. //Extras $query = "select * from extras"; $data = mysqli_query($db, $query); $num = mysqli_num_rows($data); echo "<p><b>Extras:</b></p>"; for ($i=0; $i<$num; $i++) { $row = mysqli_fetch_array($data); $extra_id = $row['extra_id']; $extra_name = $row['extra_name']; $extra_rate = $row['extra_rate']; echo "<p><input type='checkbox' name='extra_id[]' value = '$extra_id' />$extra_name <i>\$$extra_rate</i> Num Days<input type='text' name='d$extra_id' /> Num Guests<input type='text' name='g$extra_id' />"; } Link to comment https://forums.phpfreaks.com/topic/220019-help-with-dynamically-created-table-with-related-fields/ Share on other sites More sharing options...
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