mlummus Posted November 27, 2010 Share Posted November 27, 2010 I'm trying to create a table form that pulls in "Extra" choices from a table and allows users to select a number of days and number of guests for each choice. I started creating it a a checkbox field but am thinking just using the name as a label and setting days and guests to default "0" might be a better bet. Guidance from someone more experienced with this? Also, how do I store the submission (db structure - in the "reservations" table, another?). I'm new to this and feel kind of lost with this challenge. //Extras $query = "select * from extras"; $data = mysqli_query($db, $query); $num = mysqli_num_rows($data); echo "<p><b>Extras:</b></p>"; for ($i=0; $i<$num; $i++) { $row = mysqli_fetch_array($data); $extra_id = $row['extra_id']; $extra_name = $row['extra_name']; $extra_rate = $row['extra_rate']; echo "<p><input type='checkbox' name='extra_id[]' value = '$extra_id' />$extra_name <i>\$$extra_rate</i> Num Days<input type='text' name='d$extra_id' /> Num Guests<input type='text' name='g$extra_id' />"; } Quote Link to comment https://forums.phpfreaks.com/topic/220019-help-with-dynamically-created-table-with-related-fields/ Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.