BrandonLayton Posted December 6, 2010 Share Posted December 6, 2010 My first real attempt to mess with MySql. Keep getting a syntax error and I am quite confused. Error: Parse error: syntax error, unexpected '}' in /home/a8152576/public_html/MemberSystem/install1.php on line 68 Here is my php code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form id="form1" name="form1" method="post" action=""> <h2><center>Fill in the following info properly to install required databases.</center></h2> <p> <label>Host: <input type="text" name="host" id="host" /> </label> </p> <p> <label>Database User: <input type="text" name="dbUser" id="dbUser" /> </label> </p> <p> <label>Database Password: <input type="text" name="dbPass" id="dbPass" /> </label> </p> <p> <label>Desired Admin Username: <input type="text" name="adminName" id="adminName" /> </label> </p> <p> <label>Desired Admin Password: <input type="text" name="adminPass" id="adminPass" /> </label> </p> <p> <label>Email: <input type="text" name="adminEmail" id="adminEmail" /> </label> </p> <p> <input type="submit" name="submitBtn" id="submitBtn" value="Submit" /> </p> </form> <?php if(isset($_POST['submit'])){ $hostName = $_POST['host']; $dbUserName = $_POST['dbUser']; $dbPassword = $_POST['dbPass']; $adminUserName = $_POST['adminName']; $adminPassword = $_POST['adminPass']; $email = $_POST['adminEmail']; $sqlLink = mysql_connect('$hostName','$dbUserName','$dbPassword'); if(!$sqlLink){ die('Could not connect: ' .mysql_error()); mysql_close(); } else { $queryCreate = 'CREATE DATABASE member_db'; echo 'Connected successfully!'; if(mysql_query($queryCreate,$link)){ echo 'Created database!'; mysql_select_db('member_db'); $createAdminTable = "CREATE TABLE " .$adminUserName. " (`secLvl` tinyint(1) default NOT NULL,`rank` tinyint(2) default NOT NULL,`username` varChar(32) NOT NULL UNIQUE,`password` varChar(32) NOT NULL,`email` varChar(32) NOT NULL UNIQUE"; $insertAdminInfoQuery = "UPDATE " .$adminUserName. " SET `secLvl` = '5', `rank` = '10', `username` = '$adminUserName', `password` = '$adminPassword', `email` = '$email' WHERE '$adminUserName' LIMIT 1"; mysql_query($createAdminTable) or die("ERROR: " .mysql_error()); mysql_query($insertAdminInfoQuery) or die("ERROR: " .mysql_error()) } else { echo 'Error: '.mysql_error(); } } } ?> </body> </html> You can even see the error on this web page directly: http://www.ptcptc.info/MemberSystem/install1.php Thanks, Brandon Quote Link to comment https://forums.phpfreaks.com/topic/220776-database-modification-script-help/ Share on other sites More sharing options...
Spring Posted December 6, 2010 Share Posted December 6, 2010 mysql_query($insertAdminInfoQuery) or die("ERROR: " .mysql_error()) Forgot a semicolon, though I didn't even really read the whole script, just followed the error. needs to be mysql_query($insertAdminInfoQuery) or die("ERROR: " .mysql_error()); Quote Link to comment https://forums.phpfreaks.com/topic/220776-database-modification-script-help/#findComment-1143424 Share on other sites More sharing options...
BrandonLayton Posted December 6, 2010 Author Share Posted December 6, 2010 Wow. Haha thanks. I feel a little stupid now but it works edit: Well now it shows up, but when I try to submit everything just clears. Nothing echos to confirm or deny that it works and now database is created. So i am a little confounded <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Member System Install</title> </head> <body> <form id="form1" name="form1" method="post" action=""> <h2><center>Fill in the following info properly to install required databases.</center></h2> <p> <label>Host: <input type="text" name="host" id="host" /> </label> </p> <p> <label>Database User: <input type="text" name="dbUser" id="dbUser" /> </label> </p> <p> <label>Database Password: <input type="text" name="dbPass" id="dbPass" /> </label> </p> <p> <label>Desired Admin Username: <input type="text" name="adminName" id="adminName" /> </label> </p> <p> <label>Desired Admin Password: <input type="text" name="adminPass" id="adminPass" /> </label> </p> <p> <label>Email: <input type="text" name="adminEmail" id="adminEmail" /> </label> </p> <p> <input type="submit" name="submitBtn" id="submitBtn" value="Submit" /> </p> </form> <?php if(isset($_POST['submit'])){ $hostName = $_POST['host']; $dbUserName = $_POST['dbUser']; $dbPassword = $_POST['dbPass']; $adminUserName = $_POST['adminName']; $adminPassword = $_POST['adminPass']; $email = $_POST['adminEmail']; $sqlLink = mysql_connect('$hostName','$dbUserName','$dbPassword'); if(!$sqlLink){ die('Could not connect: ' .mysql_error()); mysql_close(); } else { $queryCreate = 'CREATE DATABASE member_db'; echo 'Connected successfully!'; if(mysql_query($queryCreate,$link)){ echo 'Created database!'; mysql_select_db('member_db'); $createAdminTable = "CREATE TABLE " .$adminUserName. " (`secLvl` tinyint(1) default NOT NULL,`rank` tinyint(2) default NOT NULL,`username` varChar(32) NOT NULL UNIQUE,`password` varChar(32) NOT NULL,`email` varChar(32) NOT NULL UNIQUE"; $insertAdminInfoQuery = "UPDATE " .$adminUserName. " SET `secLvl` = '5', `rank` = '10', `username` = '$adminUserName', `password` = '$adminPassword', `email` = '$email' WHERE '$adminUserName' LIMIT 1"; mysql_query($createAdminTable) or die("ERROR: " .mysql_error()); mysql_query($insertAdminInfoQuery) or die("ERROR: " .mysql_error()); } else { echo 'Error: '.mysql_error(); } } } ?> </body> </html> Quote Link to comment https://forums.phpfreaks.com/topic/220776-database-modification-script-help/#findComment-1143425 Share on other sites More sharing options...
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