Why does basename() work as follows?

[OldWest]

I am doing some study, and I am looking through an upload script.. Can someone explain to me why this is so:

 

$uploadfile = $uploaddir . basename($_FILES['userfile']['name']

);

 

From reading the manual and looking at other tutorials, it appears basename() returns the file path name thus would strip off the actual file name in the above??

 

For example if $_FILES['userfile']['name'] was mike.jpg wouldn't basename() just snag "mike"?

 

Am I right??

 

$uploaddir = '/var/www/uploads/';
$uploadfile = $uploaddir . basename($_FILES['userfile']['name']);

 

 

[OldWest]

I still don't know why basename() is used. I ran this test:

 

<form  method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<input name="submit" type="submit" value="Go >>" />
</form>

<?php
if(isset($_POST['submit'])) {
  $uploaddir = '/var/www/uploads/';
$uploadfile = $uploaddir . basename("ed.png");
echo $uploadfile;
}
?>

 

Output is: /var/www/uploads/ed.png

 

But why is basename() needed or recommended in so many examples?

 

[OldWest]

oh shit.. its too late. i misread the manual on this function! working as expected.