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Hello,

I'm trying to hide and show something if it's shown (on mouseover) and vice versa when the mouse goes over the other div. However, it doesn't work (anymore). I've got no idea what happened. I changed something and it didn't work anymore (I tried CTRL + Z, didn't work).

function menutop(hide, show){
var hide = document.getElementById(hide);
if(hide.style.visibility == 'visible') { hide.style.visibility = 'hidden'; } 
if(hide.style.visibility == 'hidden') { hide.style.visibility = 'visible'; }

var show = document.getElementById(show);
if(show.style.visibility == 'visible') { show.style.visibility = 'hidden'; }
if(show.style.visibility == 'hidden') { show.style.visibility = 'visible'; } 
}

HTML code:

<img onmouseover="menutop('dmenu', 'amenu')" src="button.png" width="30" height="30" id="amenu" style="visibility: visible;" />
<div id="dmenu" onmouseout="menutop('amenu', 'dmenu')" style="visibility: hidden;">

 

Thank you,

Link to comment
https://forums.phpfreaks.com/topic/221525-hide-show-on-mouseover/
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Nevermind, I've rewritten it:

<script type="text/javascript">
function show(box){
	document.getElementById(box).style.visibility="visible";
}
function hide(box){
	document.getElementById(box).style.visibility="hidden";
}
</script>

<img onmouseover="hide('amenu'); show('dmenu');" src="navigate.png" width="180" height="30" id="amenu" style="visibility: visible;" />
<div id="dmenu" onmouseout="hide('dmenu'); show('amenu');">

Works fine. ;)

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