AdRock Posted September 26, 2006 Share Posted September 26, 2006 I have a field in my database which is used to hold the name of an imageWhat i want to do is have an if statement so if that field has got an image name in it then do this code[code]echo "<div id='right'><h3>".strtoupper($code['title'])."</h3><p class='style3' style='text-align:left'><i>Date added: ".$code['date']."</i></p><p class='style3'><img src=images/".$code['photo']." align='right' class='right'>".nl2br($code['content'])."</p><br></div>\n";[/code]if the field is empty do this code[code]echo "<div id='right'><h3>".strtoupper($code['title'])."</h3><p class='style3' style='text-align:left'><i>Date added: ".$code['date']."</i></p><p class='style3'>".nl2br($code['content'])."</p><br></div>\n";[/code]How do i check if the field is empty? Link to comment https://forums.phpfreaks.com/topic/22167-how-to-check-if-database-field-is-empty/ Share on other sites More sharing options...
sanfly Posted September 26, 2006 Share Posted September 26, 2006 Something like this should do it:[code=php:0]if(!$code['photo']){do this}else{do that}[/code]the ! means "if the condition is false"you could also use empty()if(empty($code['photo'])){do this}else{do that}[/code] Link to comment https://forums.phpfreaks.com/topic/22167-how-to-check-if-database-field-is-empty/#findComment-99254 Share on other sites More sharing options...
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