if "is post"

phppaper · December 15, 2010

Hello,

how do you write a set of code,

when the code is only run when there is some post item pass from a html form. If no post item, other code will run.

Thanks!

scotmcc · December 15, 2010

<?php
if ($_REQUEST['test']=='post') {
	echo "The field did contain the text 'post'.";
} else {
	echo "The field did not contain the text 'post'.";
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
	<title>form test</title>
	<meta http-equiv="content-type" content="text/html; charset=iso-8859-1">
</head>
<body>
	<form action="<?php echo $PHP_SELF;?>" method="POST">
		<input type="text" name="test" id="test" />
		<input type="submit" value="submit" />
	</form>
</body>
</html>

Try playing around with this... It checks to see if something was submitted (which it sounds like what you are asking). Additionally, if you are asking specifically if something was posted from a variable called post, change the php code to look something like this:

<?php
if ($_REQUEST['test']=='post') {
	echo "The field did contain the text 'post'.";
} else {
	echo "The field did not contain the text 'post'.";
}
?>

mikecampbell · December 15, 2010

You could also check to see if the $_POST array is empty.

johnny86 · December 16, 2010

You should use something like this

<?php
// Returns TRUE if request is post otherwise FALSE
function isPost()
{
    return (strtolower($_SERVER['REQUEST_METHOD']) === "post") ? TRUE : FALSE;
}

// Now you can do:
if(isPost())
{
    // Do this if it was post
}
else
{
    // Do this when it isn't post
}
?>

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if "is post"

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