rghollenbeck Posted December 16, 2010 Share Posted December 16, 2010 I'm not trying to get a fancy looking form yet. I just want my code to be functional first. The problem seems to be with the query. The web page DOES connect to the database. I was able to run SELECT queries okay. But with the following code, I just end up with a blank page (insert.php) but when I then go back to mysqladmin and SELECT query the database, no record was added. I wonder what I'm doing wrong. inputform.php: <p>Fields marked <font color="red">*</font> are required.</p> <form method="post" action="insert.php"> <font color="red">*</font>First Name <input name="fname" type="text" value=""> <font color="red">*</font>Last Name <input name="lname" type="text" value=""><br> Address1 <input name="address1" type="text" value=""><br> Address2 <input name="address2" type="text" value=""> City <input name="city" type="text" value="">, State <input name="state" type="text" value=""> Zip Code <input name="zipcode" type="text" value=""> Email<input name="email" type="text" value=""> URL <input name="url" type="text" value=""> <?php $link = mysql_connect('rghollenbeck.fatcowmysql.com', 'rich', '***********'); if (!$link) { die('Could not connect: ' . mysql_error()); } mysql_select_db(guestlist); $Users_IP_address = $_SERVER["REMOTE_ADDR"] ; echo "<input type='hidden' name='ip' value="; echo $Users_IP_address; echo ">"; ?> <br> <input name="submit" type="submit" value="Send"> </form> insert.php: <?php $link = mysql_connect('rghollenbeck.fatcowmysql.com', 'rich', '***********'); if (!$link) { die('Could not connect: ' . mysql_error()); } mysql_select_db(guestlist); mysql_query("INSERT INTO tblMain (fname, lname, address1, address2, city, state, zipcode, email, url, telephone, ip) VALUES ($_POST[fname], $_POST[lname], $_POST[address1], $_POST[address2], $_POST[city], $_POST[state], $_POST[zipcode], $_POST[email], $_POST[url], $_POST[telephone], $_POST[ip])"); ?> Thank you. Link to comment https://forums.phpfreaks.com/topic/221817-trying-to-learn-how-to-get-form-data-into-a-mysql-database/ Share on other sites More sharing options...
rghollenbeck Posted December 16, 2010 Author Share Posted December 16, 2010 PHP version: 5.2.12 MySQL Version: 5.0.77 Sorry I didn't put that here earlier Link to comment https://forums.phpfreaks.com/topic/221817-trying-to-learn-how-to-get-form-data-into-a-mysql-database/#findComment-1147907 Share on other sites More sharing options...
rghollenbeck Posted December 16, 2010 Author Share Posted December 16, 2010 I added the following code: if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; and got the following error: Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /hermes/web06/b1946/moo.rghollenbeck/insert.php on line 10 Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near . . . at line 1. Link to comment https://forums.phpfreaks.com/topic/221817-trying-to-learn-how-to-get-form-data-into-a-mysql-database/#findComment-1147927 Share on other sites More sharing options...
rghollenbeck Posted December 16, 2010 Author Share Posted December 16, 2010 after I fixed the stupid mistakes, such as forgetting to put the single quote around the field names, etc., other more specific errors began to emerge. As I fixed them, one by one, eventually the script began to work correctly. However, it reported a "0" on the page. I don't know why it is doing that, but I don't care. I can redirect the page back to the original page, maybe with a javascript alert thanking the visitor for their submission. Link to comment https://forums.phpfreaks.com/topic/221817-trying-to-learn-how-to-get-form-data-into-a-mysql-database/#findComment-1148010 Share on other sites More sharing options...
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